How to split a string by a specific pattern in number of characters?

How to split a string by a specific pattern in number of characters?

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How to split a string by a specific pattern in number of characters?
Tag : python , By : Jesse
Date : January 12 2021, 09:11 PM

wish of those help As I understand you want a list of lists, and that the list is 14,000 characters long, and there won't be any errors like missing or spurious characters to worry about.
So a nested list comprehension will do this job. In this example I've shortened your sample input by 8 characters to make it evenly divisible by 14. This assumes perfect input data and doesn't check anything.
l = "4024f003503140402510033031204024f0038030d04024f0036030a04024e0039030c0"
print([[s[2:6], s[6:10], s[10:14]] for s in [l[m:m+14] for m in range(0, len(l), 14)]])
[['24f0', '0350', '3140'], ['2510', '0330', '3120'], ['24f0', '0380', '30d0'], ['24f0', '0360', '30a0'], ['24e0', '0390', '30c0']]
l = "4024f003503140402510033031204024f0038030d04024f0036030a04024e0039030c0"
def sensor(l):
    assert len(l) % 14 == 0, f"Input length of {len(l)} is not a multiple of 14"
    for m in range(0, len(l), 14):
        s = l[m:m+14]
        assert s[:2] == "40", f"Missing Ack at position {m}"
        yield [s[:4], s[4:8], s[8:12]]

sensor_list = [s for s in sensor(l)]


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Javascript split to split string in 2 parts irrespective of number of spit characters present in string

Tag : javascript , By : MikeW
Date : March 29 2020, 07:55 AM
To fix this issue I want to split a string in Javascript using split function into 2 parts. , You can use match instead of split:
splited = str.match(/^([^&]*?)&(.*)$/);
["123", "345&678&910"]

JavaScript: Split string by characters only or by characters + number if present

Tag : javascript , By : Roel
Date : March 29 2020, 07:55 AM
seems to work fine Split on every position where the following character is a letter. This can be done with a lookahead:
> "a2sd12a3".split(/(?=[a-z])/i)
["a2", "s", "d12", "a3"]

Split a string based on a specific number of characters in VB.Net

Tag : vb.net , By : k19k
Date : March 29 2020, 07:55 AM
will help you You need to be careful about parsing dates: a few countries use month-day-year and many others use day-month-year.
To give you an idea of what is possible:
Option Infer On
Option Strict On

Module Module1

    Sub Main()
        Dim s = "31012001"
        Dim d As DateTime
        d = DateTime.ParseExact(s, "ddMMyyyy", Globalization.CultureInfo.InvariantCulture)

        ' if you need a string representation of the date:
        Dim q = d.ToString("dd/MM/yyyy")


        ' leaving the date as a date, as it should be, and presenting it as a string:

        s = "01312001" ' not in ddMMyyyy format
        If DateTime.TryParseExact(s, "ddMMyyyy", Nothing, Globalization.DateTimeStyles.None, d) Then
            Console.WriteLine("Converted successfully as " & d.ToString("dd/MM/yyyy"))
            Console.WriteLine("Could not parse " & s & " as dd/MM/yyyy")
        End If


    End Sub

End Module

Regex to split String on pattern but with a minimum number of characters

Tag : java , By : baumichel
Date : March 29 2020, 07:55 AM
I hope this helps you . Instead of using split, you could also match your values using a capturing group. To make the dot also match a newline you could use Pattern.DOTALL
String regex = "\\s*(.{30}[^.]*\\.|.+$)";

Java: Split string by number of characters but with guarantee that string will be split only after whitespace

Tag : java , By : user122937
Date : March 29 2020, 07:55 AM
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