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How verify that 3 numbers in sequence are equals?


How verify that 3 numbers in sequence are equals?

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How verify that 3 numbers in sequence are equals?
Tag : java , By : Suresh S
Date : January 12 2021, 09:11 PM

Does that help As the others already said, u r overshooting the boundaries of your array. You need to stop the loop 2 earlier to prevent.
You possably want to use something like that:
    int sequenceLength = 3;
    for (int i = 0; i <= M.length - sequenceLength; i++) {
        boolean correct = true;
        for (int j = 0; j < sequenceLength && (correct = (M[i] == M[j+i])); j++);

        if (correct){
            ValuePoint = 0;
        } else {
            PExtraM = i;
            ValuePoint = 30;
            break;
        }
    }

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Does Moq.Mock.Verify() compare parameters using identity or .Equals()?


Tag : chash , By : user152423
Date : March 29 2020, 07:55 AM
This might help you Moq will compare by identity, it will be looking for the exact instance that you specified using identity. If this is not what you want, and you are looking for equals comparison instead, you can use It.Is:
mockObj.Verify(foo => foo.someMethod(It.Is<MyObject>(m => m.Equals(anotherObj))));

Ant - Verify if two binaries (jar) are strictly equals


Tag : ant , By : user187383
Date : March 29 2020, 07:55 AM
To fix this issue Ant core provides a checksum task :
Generates checksum for files. This task can also be used to perform checksum verifications.
<checksum file="path/to/foo.jar" property="fooMD5"/>

<fail message="Binaries not equal !!">
 <condition>
  <not>
   <checksum file="path/to/fooo.jar" property="${fooMD5}"/>
  </not>
 </condition>
</fail>

Algorithm to verify if a two-dimensional array has two equals rows


Tag : java , By : Matt Watson
Date : March 29 2020, 07:55 AM
Hope this helps , Here is how i would do it:
int[][] array = { { 1, 2, 3, 4, 5, 6 },
            { 7, 6, 8, 3 }, 
            { 1, 2, 3, 4 },
            { 1, 2, 3, 9, 5, 6, 32, 3125423 },
            { 8, 3 }, 
            { 1, 2, 3, 4, 5, 6 } };//same as first row
    external: for (int i = 0; i < array.length; i++) {
        for (int j = i + 1; j < array.length; j++) {
            if (Arrays.equals(array[i], array[j])) {
                System.out.println("Row: " + i + " is the same as row: " + j+" (warning! 0 oriented!)" );
                break external;
            }
        }
    }

Is there a way to compare how similar a sequence of numbers is to another sequence of numbers in Ruby?


Tag : arrays , By : Boris
Date : March 29 2020, 07:55 AM
To fix the issue you can do I'm trying to compare how similar 2 sequences are to eachother in Ruby. For example, 1234657890 to 1234567890 is 80% similar. I've thought about decreasing the number by 1 digit and then checking but then it makes that example 40% similar , You could do something like:
num_str1 = '1234567890'
num_str2 = '1234657890'

num_str1.chars.zip(num_str2.chars).count { |a, b| a == b }
  #=> 8

Given an array of unique numbers, list the combination of numbers which sum equals to given integer


Tag : javascript , By : Dré
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , You could use a temporary array and the index and iterate the next index by either taking the actual value or not.
function subsetSum(array, sum) {

    function iter(index, temp, s) {
        if (s === sum) return result.push(temp.slice());              // exit sum found
        if (index >= array.length) return;                            // exit index over
        iter(index + 1, temp.concat(array[index]), s + array[index]); // take value
        iter(index + 1, temp, s);                                     // omit value
    }

    var result = [];
    iter(0, [], 0);
    return result;
}

console.log(subsetSum([4, 2, 8, 11, 14, 6, 1], 20).map(a => a.join(' ')));
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