Why does using a range for loop gives different output than using a regular for loop in this scenario?

Why does using a range for loop gives different output than using a regular for loop in this scenario?

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Why does using a range for loop gives different output than using a regular for loop in this scenario?
Tag : cpp , By : 3NZ0
Date : January 12 2021, 07:00 PM

it should still fix some issue What I would like to achieve , i is declared as an integer So this comparison
if(i!=val[val.size()] ...
    bool first = true;        
    for ( const auto &item : val ) 
        if ( !first ) std::cout << ", ";
        else first = false;

        std::cout << item;
    std::cout << '\n';
    for ( const auto &item : v )
        std::cout << item;
        std::cout << ( item == v[v.size() - 1] ? "\n" : ", " );
#include <iostream>
#include <vector>

int main() 
    std::vector<double> v = { 1.1, 2.2, 3.3, 4.4, 5.5, 6.6, 7.7, 8.8, 9.9 };

    for ( const auto &item : v )
        std::cout << item;
        std::cout << ( item == v[v.size() - 1] ? "\n" : ", " );

    return 0;
1.1, 2.2, 3.3, 4.4, 5.5, 6.6, 7.7, 8.8, 9.9

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Convert a list comprehension loop into a regular for loop without creating an infinite loop

Tag : python , By : Shitic
Date : March 29 2020, 07:55 AM
wish of those help I am trying to convert this list comprehension: , You can do two things:
for s in cfg[:]: 
new_cfg = []
for s in cfg:

cfg = new_cfg

range based for loop vs regular iterator for loop

Tag : cpp , By : unfool
Date : March 29 2020, 07:55 AM
help you fix your problem The answer is what Magnus already stated: Yes, it is a normal behavior. Range loops are for cases when we are interested in examining every item in a collection (unless we break out sooner) and aren't interested in doing anything with the container itself. Like it was already stated, range loops are optimized that way, e.g. it indeed computes the finishing condition only once. In my opinion, this is a very nice and welcome addition to the variety of loop options in c++, since we do often face this very exact situation: we get a container and are interested in simply going through them one by one in either const or non-const fashion.

VBA loop through range and output if complete range is empty

Tag : vba , By : beebob
Date : March 29 2020, 07:55 AM
Hope that helps I have searched a lot about my question but could not find the answer I need. , Your are doing well. Just need to loop thru the range like this.
Sub rowEmpty()
    Dim rng As Range, r As Range
    Set rng = Range("B2:DT97138")

    For Each r In rng.Rows
        If WorksheetFunction.CountA(r) = 0 Then
            Cells(r.Row, 125) = "Empty"
            Cells(r.Row, 125) = "Not Empty"
        End If
    Next r
End Sub

Scenario output gives wrong answer upon second loop

Tag : cpp , By : Sonal
Date : March 29 2020, 07:55 AM
wish help you to fix your issue While this may not completely fix your issue, you need to at least reinitialize your volFilled value back to 0.0 between scenarios. Otherwise you're just continuing from the previous scenario's volFilled, and that explains why the second test that you did with switching the scenarios yielded the same output. After the first scenario where volFilled reaches 20.0, it won't execute the logic inside the considion while (volFilled < V) in the second scenario because at this point, volFilled = 20 while V = 10.

C++ range for loop different than regular for loop

Tag : cpp , By : 40a
Date : March 29 2020, 07:55 AM
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