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How to convert stream into variables in typescript


How to convert stream into variables in typescript

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How to convert stream into variables in typescript
Tag : javascript , By : Robert M
Date : January 12 2021, 07:00 PM

will be helpful for those in need I think the problem here is that if you're coming from C++ into the Javascript world there is a big conceptual difference in how the code you write is actually executed. C++ heavily relies on synchronous execution while the Javascript world is more focused on asynchronous execution.
The concrete problem you're trying to solve would be achieved in this way using the asynchronous Node APIs you attempt to use:
// imports, or require()s as in your code are like conceptually equivalent
// to #include in C++, hence should be at the beginning of the file, not somewhere
// in the middle.
import * as fs from 'fs'
import * as readline from 'readline'

const graphsMain = () => {
    let lineReader = readline.createInterface({
        input: fs.createReadStream('file.in')
    });

    let lineCount = 0;
    let nodes: number | undefined
    let edges: number | undefined
    let buffer: number[][] = []
    lineReader.on('line', function (line) {
        console.log('Line from file:', line);
        if (lineCount == 0) {
          nodes = parseInt(line) 
        } else if (lineCount == 1) {
          edges = parseInt(line)
        } else {
          const coordinates = line.split(' ').map((item) => parseInt(item)) 
          buffer.push(coordinates)
        }
        lineCount++
    });

    lineReader.on('close', function () {
        console.log('end. I got these values:', nodes, edges, buffer)   
    });
}

graphsMain();

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Convert java.util.stream.Stream to Scala Stream


Tag : scala , By : Deepak Poondi
Date : March 29 2020, 07:55 AM
Hope that helps The current version of JavaConverters and JavaConversions don't offer conversions between Java Stream and Scala Stream because of differences at roadmaps.
Java 8, the version where java.util.stream.Stream was introduced, was released at Mar 2014 while Scala 2.11.0 was officially released at Apr 2014. So there was no time to change Scala 2.11 plans to add better integration with Java 8 features. In fact, better support to Java 8 is planned for Scala 2.12 (see the roadmap here and also this presentation from Adrian Moors).
import java.nio.file.Path
import java.nio.file.Files

import scala.collection.JavaConverters._

object Foo {
  def streamFiles(path: Path): Stream[Path] = {
    Files.newDirectoryStream(path).iterator().asScala.toStream
  }
}
import scala.compat.java8.StreamConverters._

val numbers: java.util.List[Int] = java.util.Arrays.asList(1, 2, 3)
numbers.stream().toScala[Stream]

Typescript How to convert array values to class variables


Tag : angular , By : Valentine
Date : March 29 2020, 07:55 AM
hop of those help? Suppose key is 'abc' and value 'true', I should be able to access 'this.abc'; and this should return me true , Try this:
Class A {
    public someFun(){

        const obj = this;

        this.external.getData().subscribe((externalStream: Array<someType>) => {
            for(let i:number = 0; i < externalStream.length; i++){
                obj[externalStream[i].key] = externalStream[i].value;
            }
        })
    }
}

Type for nodejs stream.Stream in typescript?


Tag : node.js , By : user130518
Date : March 29 2020, 07:55 AM
it should still fix some issue You can find all node types in @types/node package. Just add this package to your project and that's it.

Convert Typescript class to string, with getter and setter instead of private variables


Tag : json , By : Sergio Rudenko
Date : March 29 2020, 07:55 AM
I hope this helps . I have the following Typescript code: , There are 2 things to keep in mind here:
let a = {
    user: "Foo",
    data: {
        name: "Bar"
    }
};

JSON.stringify(a, ["user", "data"]);
let a = {
    user: "Foo",
    data: {
        user: "Bar"
    }
};

JSON.stringify(a, ["user", "data"]);
abstract class Stringifyiable {
    private isStringifyiable(value): boolean {
        return value != null && (typeof value === 'object' || typeof value === 'function') && value['getJsonKeys'] && typeof value['getJsonKeys'] === 'function';
    }

    public getJsonKeys(): string[] {
        let keys = Object.keys(this.constructor.prototype);
        keys.forEach(key => {
            if (this.isStringifyiable(this[key])) {
                keys = keys.concat(this[key].getJsonKeys());
            }
        });

        return keys;
    }

    public toJSONString(): string {
        return JSON.stringify(this, this.getJsonKeys());
    }
}



class Foo extends Stringifyiable {
    private _id: number;
    private _desc: string;
    private _user: Bar;

    constructor(id: number, desc: string, user: Bar) {
        super();
        this._id = id;
        this._desc = desc;
        this._user = user;
    }

    public get id(): number {
        return this._id;
    } 

    public set id(value: number) {
        this._id = value;
    }

    public get desc():string {
        return this._desc;
    } 

    public set desc(value: string) {
        this._desc = value;
    }

    public get user(): Bar {
        return this._user;
    } 

    public set user(value: Bar) {
        this._user = value;
    }
}



class Bar extends Stringifyiable {
    private _name: string;
    private _surname: string;

    constructor(name: string, surname: string) {
        super();
        this._name = name;
        this._surname = surname;
    }

    public get name(): string {
        return this._name;
    } 

    public set name(value: string) {
        this._name = value;
    }

    public get surname():string {
        return this._surname;
    } 

    public set surname(value: string) {
        this._surname = value;
    }
}

let foo = new Foo(1, 'something', new Bar('foo', 'bar'));
//this will output {"id":1,"desc":"something","user":{"name":"foo","surname":"bar"}}
foo.toJSONString();

How to make typescript stream reading code not to proceed before stream is ended?


Tag : angular , By : Sinisa Ruzin
Date : March 29 2020, 07:55 AM
hope this fix your issue So it turned out that the promise works just like I thought. So yes, just add a promise and resolve it in correct place. Note that there's no error handling (fail + reject) and that unlike the question, this answer adds features in local variable features that is returned in the promise.
async getFeaturesFromStream() : Promise<MyFeature[]> {
    return new Promise<MyFeature[]>((resolve) => {
        const features: MyFeature[] = [];
        const url = 'http://localhost:19100/pn/api/v1/fetch?cgid=22&north=6822169.0&east=24487155.0&south=6821411.0&west=24485674.0';
            oboe(url)
            .node('!', (row) => {
                console.log(row);
                features.push(row);
            })
            .on('end', () => {
                console.log('only after this we can proceed. nbr of items' + features.length);
                resolve(features);
            });
        });         
}

async getFeatures() : Promise<void> {
    const features = await getFeaturesFromStream();
    codeNotTobeCalledBeforeArrayReady();
}
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