Determine if one Map is a subset of another Map

Determine if one Map is a subset of another Map

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Determine if one Map is a subset of another Map
Tag : flutter , By : chorn
Date : January 12 2021, 01:40 AM

fixed the issue. Will look into that further You can get each MapEntry of subset candidate and check if original map contains the same value. If value is a collection, then it has to be compared using DeepCollectionEquality.
Here is my code:
import 'package:collection/collection.dart'; // import for DeepCollectionEquality

bool isSubset(Map map, Map subsetCandidate) {
  return subsetCandidate.entries.every(
      (entry) => DeepCollectionEquality().equals(entry.value, map[entry.key]));

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How can I determine if a given DTD a subset of another?

Tag : xml , By : eferro
Date : March 29 2020, 07:55 AM
help you fix your problem DTDs are really just context-free grammars in disguise. A grammar G represents the set of possible legal strings that comprise the unstated language L(G) that grammar represents.
What you are asking is tantamount to determining if you have G1 and G2, whether L(G1) is a subset of L(G2). My language theory is getting rusty and I don't remember if this is computable in general or not, but my guess this is really hard, because you have to demonstrate that an arbitrary derivation in G1 always has a derivation in G2.
<?xml version='1.0' ?>
<!DOCTYPE orderform [

<!ELEMENT orderform (name,company,address,items) >
<!ELEMENT name ( firstname, lastname )>
<!ELEMENT firstname ( #PCDATA )>
<!ELEMENT lastname ( #PCDATA )>
<!ELEMENT company ( #PCDATA )>
<!ELEMENT address ( street, city, country )>
<!ELEMENT street ( #PCDATA )>
<!ELEMENT city( #PCDATA )>
<!ELEMENT country ( zipcode | nation )>
<!ELEMENT zipcode ( #PCDATA )>
<!ELEMENT nation ( #PCDATA )>
<!ELEMENT items (item)+ >
<!ELEMENT item ( partnumber, quantity, unitprice)>
<!ELEMENT partnumber ( #PCDATA )>
<!ELEMENT quantity ( #PCDATA )>
<!ELEMENT unitprice  ( #PCDATA )>

<?xml version='1.0' ?>
<!DOCTYPE orderform [

<!ELEMENT orderform (name,company,location,item) >
<!ELEMENT name ( firstname, lastname )>
<!ELEMENT firstname ( #PCDATA )>
<!ELEMENT lastname ( #PCDATA )>
<!ELEMENT company ( #PCDATA )>
<!ELEMENT location ( street, city, country )>
<!ELEMENT street ( #PCDATA )>
<!ELEMENT city( #PCDATA )>
<!ELEMENT country ( zipcode | nation )>
<!ELEMENT zipcode ( #PCDATA )>
<!ELEMENT nation ( #PCDATA )>
<!ELEMENT item ( partnumber, unitprice)>
<!ELEMENT partnumber ( #PCDATA )>
<!ELEMENT quantity ( #PCDATA )>
<!ELEMENT unitprice  ( #PCDATA )>

C:\DMS\Domains\XML\Analyzers\SmartDifferencer\Source>DMSSmartDifferencer XML -SuppressSourceCodeForRenamings C:\DMS\Domains\XML\Tool
s\DTD2COBOL\orderform.xml C:\DMS\Domains\XML\Tools\DTD2COBOL\orderform2.xml
Copyright (C) 2009 Semantic Designs; All Rights Reserved
XML SmartDifferencer Version 1.1.1
Copyright (C) 2009 Semantic Designs, Inc; All Rights Reserved; SD Confidential
Powered by DMS (R) Software Reengineering Toolkit
*** Unregistered SmartDifferencer Version 1.1
*** Operating with evaluation limits.

*** Parsing file C:/DMS/Domains/XML/Tools/DTD2COBOL/orderform.xml ...
*** Parsing file C:/DMS/Domains/XML/Tools/DTD2COBOL/orderform2.xml ...
*** Creating suffix tree ...
*** Determining maximal pairs ...
*** Sorting maximal pairs ...
*** Determining differences ...
*** Printing edits ...
Rename 4.1-9.44 to 4.1-9.45 with 'address'->'location' and 'items'~>'item'
Delete 15.1-15.25 merging 15.18-15.21 into 4.44-4.47
<<!ELEMENT items (item)+ >
Delete 16.30-16.38 merging 16.30-16.38 into 15.18-15.28 with 'quantity'~>'partnumber'
<                             quantity,

Function to determine if a set is subset of another one

Tag : development , By : Luciano Campos
Date : March 29 2020, 07:55 AM
it should still fix some issue Well, given two sets A and B, A is a subset of B precisely when their intersection equals A. Since Mathematica has the Intersection[] function, you can use that. Similarly, you could see whether or not there are any elements in Complement[A,B], etc.

How to determine if one regex is subset of another?

Tag : regex , By : THD
Date : March 29 2020, 07:55 AM
This might help you There are obviously a lot of ways to do this - any logical argument could constitute a valid proof. However, an instructive method of answering this question is to use algorithms to compute an answer to the general question.
Two languages are equal if each contains the other. If one language contains another, the difference of the contained language and the containing language is the empty set. Therefore, if two languages A and B are equal, then A \ B and B \ A are both empty; and if A \ B and B \ A are both empty, then A and B must be equal.

Determine subset using recursion

Tag : haskell , By : John Miller
Date : March 29 2020, 07:55 AM
I hope this helps you . I am trying to write a function subset which takes two lists and determines whether the elements of the first appear in the second.
subset (x:xs) ys
 | elem x ys = subset (x:xs) ys
                   -- ^^^^^^ --

An algorithm to determine a subset sequence in O(n)?

Tag : algorithm , By : user169463
Date : March 29 2020, 07:55 AM
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