Prevent the duplicate function onchange event jQuery

Prevent the duplicate function onchange event jQuery

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Prevent the duplicate function onchange event jQuery
Tag : javascript , By : Sigtryggur
Date : January 11 2021, 05:14 PM

I think the issue was by ths following , Instead of writing code twice, you can trigger the event (change) using jQuery's .trigger():
    if($(this).val() == "01"){
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="show">
    Sample Text
<select name="test" id="selectTest">
    <option value="00"></option>
    <option value="01">Click this to hide text</option>
    <option value="02">Click this to show text</option>

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How Change calling function of onChange event using jQuery

Tag : javascript , By : user133834
Date : March 29 2020, 07:55 AM
wish helps you I have this code which can display drop down in div tag of html. In this I have set one function "hello()" to that drop down through jquery but the problem is that its not calling that function. , You need this.

jQuery function is not calling onchange event in Spring MVC

Tag : java , By : Lathentar
Date : March 29 2020, 07:55 AM
may help you . Well there is one thing you can just check it out once that are u including that all the java script libraries into the all the page where u using that all libraries. ??
it means that if i am including other page then u still need to include that libraries into the other pages as well.

Jquery/AJAX function not working onChange Event

Tag : javascript , By : krs
Date : March 29 2020, 07:55 AM
it fixes the issue Clearly, you should not put that php inside the success callback of the AJAX response. I can't imagine what good this could do. Just erase those lines.
I don't know what that php generates, but it looks like it generates a syntax error in function get_data().

jQuery onChange event handler firing function twice

Tag : javascript , By : Robert M
Date : March 29 2020, 07:55 AM
To fix this issue The reason why it's firing twice is because your on change element fires for every class with the name item. If you look through your code you can see that on top of giving every table column the class item, you are also passing the item class to each row that is added. So the event fires twice, once for the row and once for the item column.
The code that's giving you the problem is
prot.attr("class", id + " item")
prot.attr("class", "item-" + id)

how to prevent duplicate onChange values within map loop

Tag : reactjs , By : MikeW
Date : March 29 2020, 07:55 AM
will help you The problem is that all your comments refer to the same value in your component-state. I wanted to touch upon this in your earlier question.
What you should be doing is separating your Grid markup into its own component like this:
import React, { Component } from "react";
import Button from '@material-ui/core/Button';
import TextField from '@material-ui/core/TextField';
import Grid from '@material-ui/core/Grid';
import Typography from '@material-ui/core/Typography';
import Paper from '@material-ui/core/Paper';
import Divider from '@material-ui/core/Divider';
import Image from './Image';
import moment from 'moment';
import Comment from './Comment';

class ImageContainer extends React.Component{
    state = {
      isComment: false,
      comment_body: ""

    handleCommentChange = (e) => {
           comment_body: e.target.value

    writeComment = (id)  => {
            isComment: this.state.isComment ? '' : id // check if you state is filled to toggle on/off comment

    commentSubmit = (e) => {
    // Axios.post('/images/newComment', this.state.comment_body).then( (response )=> {
    //     const newComment = { ...response.data};
    //     console.log(newComment);
    //     this.setState({
    //         comment_body: ''
    //     })
    // })

       const { img } = this.props
           <Grid item sm={12} md={12} key={img.id} style={{ margin: '30px 0px'}}>
               <Paper style={{padding:'20px 20px'}}>
         {/* // empty image_title */}
               <Typography style={{ padding: '30px 5px', letterSpacing:'8px', textTransform:'uppercase'}} variant="h4" align="center">{img.image_title}</Typography> 
               <Divider style={{ width: '150px', margin:'10px auto', backgroundColor:'#000000'}} variant="middle" />
               <Image image_url={img.img_url} />   
               <Typography variant="h6" align="center">{img.user.username}</Typography> 
               <Typography variant="h6" align="center">{moment(img.created_at).calendar()}</Typography> 
               <Button onClick ={() => this.writeComment(img.id)} variant="outlined" component="span" color="primary"> 
            {this.state.isComment === img.id ? "Close" : "Write A Comment"}
            {/* here were prevent comments being selected for all items in the array, renders the comment form you clicked on.  */}
            {this.state.isComment === img.id ?
               <Comment onSubmit={this.commentSubmit} 
                            commentBody={this.state.comment_body } 
            : null}
            {/* hide delete button when user enters comment */}
            {!this.state.isComment ? <Button style={{margin: '0px 20px'}} onClick={() => this.deleteImg(img.id)} variant="outlined" component="span" color="primary">
            </Button> : null}


export default ImageContainer
import ImageContainer from "./ImageContainer"
{this.state.images.length > 0 ? (
        this.state.images.map( (img, i) => (     
            <ImageContainer img={img}/>
    ) : (
        <Grid item md={8}>
            <Typography>No Images yet</Typography>
import React from "react";

const Comment = props => {
  return (
    <form onSubmit={props.onSubmit}>

export default Comment;
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