How do we assign the URL to the respective image which is randomly appearing?

How do we assign the URL to the respective image which is randomly appearing?

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How do we assign the URL to the respective image which is randomly appearing?
Tag : jquery , By : chintown
Date : January 11 2021, 05:14 PM

help you fix your problem You are assigning the title of the image and src together. Change this
 $("#image_slider").attr("src",img_arr[pic] +" "+ links_arr[links]);
 $("#image_slider").attr({"alt": img_arr[pic], "src": links_arr[links]+img_arr[pic]});

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Randomly assign an image a value, then pass an animation

Tag : javascript , By : Tony Siu
Date : March 29 2020, 07:55 AM
To fix this issue I'm looking to create an array with all my images in, I then want to assign a random image a value between 1 - 10. The value it ends up with will be a timed countdown in seconds until my Jquery animation is run. The code will then loop over and over, until the person leaves that page. , Try this
var iconImgs = new Array('star','coffee','picture','code');
var max = iconImgs.length;
var times = Math.floor((Math.random()*10)+1);

$(document).ready(function () {

    setInterval(function () {
        var num = Math.floor((Math.random() * max));

        $("."+iconImgs[num]+"-icon").effect("bounce", {
            times: times
        }, 400);
    }, 400);


filter array in odd and even and then assign into key and value respective value

Tag : php , By : Hibame
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I would approach it not so much as even and odd as alternating entries. So we use a "normal" for loop with an $i++ increment on it, but also add in a ++$i within the code. This means that each time through the loop, $i actually gets incremented twice.
for($i = 0; $i < count($inputArray); $i++)
    if(isset($inputArray[$i]) && isset($inputArray[$i+1]))
        $resultArray[] = array("number"=>$inputArray[$i]["number"], "carrier"=>$inputArray[++$i]["carrier"]);

How to retrieve large amount of image from resources and randomly assign to different Picturebox?

Tag : visual-studio-2010 , By : Vick Aita
Date : March 29 2020, 07:55 AM
it fixes the issue One way (could be not the best in performance): You need to generate the random numbers and store it in a list. If the generated number is already present in the list, you get another one... at the end... you will have all the numbers
This one is better:
    Dim rand As New Random()
    Dim new_list As New List(Of Image)
    Do While Pictures.Count > 0
        ' Move a random Image to the new list.
        Dim i As Integer = rand.Next(0, Pictures.Count)

How to get respective text and image from the respective recyclerview item in floaty upon clicking a button?

Tag : android , By : Steve M
Date : March 29 2020, 07:55 AM
Hope this helps If you take a look at the Floaty code here. You will notice it uses SingletonPattern. Hence that is the reason it works for the first time but after that, it shows incorrect data. One solution that comes is to extend the Floaty class, and add your own createInstance method. The body of method would be something like this:
public static synchronized Floaty createInstance(Context context, View head, View body, int notificationId, Notification notification, FloatyOrientationListener
        floatyOrientationListener) {
    if (floaty == null) {
        floaty = new Floaty(context, head, body, notificationId, notification, floatyOrientationListener);
    }else {
        floaty = null;
        floaty = new Floaty(context, head, body, notificationId, notification, floatyOrientationListener);
    return floaty;

Issue with numbers not appearing in box when respective button is pressed

Tag : java , By : Sergio Rudenko
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , Just append the number to the JTextField(using setText(String) and getText()) in the actionPerformed function.
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