Can't change instance attribute of my class?

Can't change instance attribute of my class?

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Can't change instance attribute of my class?
Tag : python-3.x , By : baylisscg
Date : January 11 2021, 05:14 PM

will help you print prints a string to sys.stdout and returns None. you should change the line
self.name = print("client" + str(self.c_counter));
self.name = "client" + str(self.c_counter)

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How can I change an attribute of a parents class instance

Tag : python , By : acolomba
Date : March 29 2020, 07:55 AM
Hope this helps You have a few problems:
1) Function inherts from MainApp - don't do that - its weird!!
class MainApp(App):

    link_buttons = 0

    def build(self):
        layout = GridLayout(cols=1, padding=1, spacing=10,
                    size_hint=(None, None), width=10)
        sv = ScrollView(size_hint=(None, None), size=(200, 400),
             pos_hint={'center_x': .5, 'center_y': .5}, do_scroll_x=False)
        self.layout = layout
        root = RootWidget()
        c = CustomLayout()
        s = Scrollbox()

        get_buttons = Button(
            text='Get links',
            size_hint=(1, 0),
            pos=(20, 20))

        return root

    def buttons(self, btn):

        layout = self.layout  
        self.link_buttons += 1

        for buttn in range(20):
            btn = Button(text='test', size=(200, 50),
                     size_hint=(None, None))


Why is `__dict__` attribute of a custom Python class instance a descriptor of the class, instead of an actual attribute

Tag : python , By : user158220
Date : March 29 2020, 07:55 AM
Any of those help It's tempting to say that __dict__ has to be a descriptor because implementing it as a __dict__ entry would require you to find the __dict__ before you can find the __dict__, but Python already bypasses normal attribute lookup to find __dict__ when looking up other attributes, so that's not quite as compelling as it initially sounds. If the descriptors were replaced with a '__dict__' key in every __dict__, __dict__ would still be findable.
There's some space savings by not having a key for '__dict__' in every __dict__, but that's not the big reason. There's also time saved by not having to set a '__dict__' key, and time and space saved by not creating a circular reference, and these benefits are all really nice, but they're still probably smaller than the next thing.

Why does the semantics of a python class attribute change after assignment to an instance?

Tag : python , By : user119605
Date : March 29 2020, 07:55 AM

How to change a class attribute into an instance attribute Python Programming

Tag : python , By : Andrew Mattie
Date : March 29 2020, 07:55 AM

Why instance attribute created by merging other attribute doesn't change,even when original attribute gets override

Tag : python , By : IanM
Date : March 29 2020, 07:55 AM
will be helpful for those in need Because details is created from the original values. After the concatenation occurs, it's entirely independent of the other values. If you want a dynamically constructed string using the current values of name/author, use a property to compute details dynamically on access (without storing it as an attribute at all):
class Book(object):
    def __init__(self, name, author):
        self.name = name
        self.author = author
        # Don't make a `details` attribute at all

    def details(self):
        # This method is called whenever you refer to `somebook.details`
        return self.name + ' written by ' + self.author
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