To get output of movie with its genre

To get output of movie with its genre

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To get output of movie with its genre
Tag : php , By : demize95
Date : January 11 2021, 05:14 PM

hope this fix your issue Each $row contains the title ("Snitch") and ONE genre. You loop through this, so it's echoing the title with each row. Try this replacement:
   $oldtitle = $title = '';
   while ($row = $stmt->fetch()){

   $title= $row['title'];
   if ( $oldtitle == $title ) $title = '';
   else  $oldtitle = $title;

   $genre= $row['genre'];
        <h1> <?php echo $title ; ?> </h1>
            <h1> <?php echo $genre ; ?> </h1>

   <?php } ?>

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SQL - Get highest rated movie by genre

Tag : sql , By : Grik
Date : March 29 2020, 07:55 AM
this will help You could calculate the rating by summing all ratings for a movie in a subquery. Another subquery could calculate the highest rating per genre. By joining them together, you'd filter only the top movies per genre:
select  *
from    Movie m
join    Genre g
on      g.movieId = m.movieId
join    (
        select  r.mid
        ,       sum(Rating) as SumRating
        from    Rating r
        group by
        ) r
on      r.mid = m.movieId
join    (
        select  g.id as gid
        ,       max(SumRating) as MaxGenreRating
        from    (
                select  r.mid
                ,       sum(Rating) as SumRating
                from    Rating r
                group by
                ) r
        join    Genre g
        on      g.movieId = r.mid
        group by
        ) filter
on      filter.gid = g.id
        and filter.MaxGenreRating = r.SumRating

Average Genre per Movie in Genre SQL Server 2012

Tag : sql-server , By : quicky
Date : March 29 2020, 07:55 AM
this will help I solve problems like this by first building the innermost query with the main info that I want, and then work outwards.
The core information needed is:
select movie_id, count(*) from genres_movies group by movie_id
select G.name, Round(avg(numgenres),2) as MuddleFactor
from genres_movies GM

inner join
(select movie_id, count(*) as numGenres
 from genres_movies
 group by movie_id) MNG 
 on MNG.movie_id = GM.movie_id

inner join genres G
on GM.genre_id = G.id

group by G.name
order by MuddleFactor desc

Using tensorflow.js to predict movie desirability based on genre

Tag : javascript , By : Jojo
Date : March 29 2020, 07:55 AM
hope this fix your issue The number of samples should match the number of targets, otherwise model can not learn. I updated your example, added another sample, and another target, and corrected the shapes.
// Define a model for linear regression.
const model = tf.sequential();
model.add(tf.layers.dense({ units: 1, inputDim: 3 }));

// Prepare the model for training: Specify the loss and the optimizer.
model.compile({ loss: 'meanSquaredError', optimizer: 'sgd' });
// Generate some synthetic data for training.

//[action, adventure, romance]
const xs = tf.tensor2d([[1, 1, 0], [1, 0, 1]]);
//target data should be rating from 1 to 5
const ys = tf.tensor2d([[3], [2]]);

// Train the model using the data.
model.fit(xs, ys).then(() => {
  // Use the model to do inference on a data point the model hasn't seen before:
  // Open the browser devtools to see the output
  model.predict(tf.tensor2d([[1, 0, 0]])).print();

Analysis of Movie Ratings percentages across Occupation and Movie Genre

Tag : python , By : 22.
Date : March 29 2020, 07:55 AM
I hope this helps you . When you reduceByKey you have to return the same structure you have received, otherwise the next time you will meet a value of the same key and will try to reduce it your function will not work.
You have tested only on two elements so you haven't seen it, but if you'll try with 3...:
 rdd = sc.parallelize([('librarian', (1, [0, 0, 1, 0])), ('librarian', (1, [0, 1, 0, 0])),\
                      ('librarian', (1, [0, 1, 0, 0]))])

result = rdd.reduceByKey(lambda x, y: ((x[0]+y[0]),\
                            (x[1][0]+y[1][0]), (x[1][1]+y[1][1]), (x[1][2]+y[1][2]), (x[1][3]+y[1][3]) ))
 rdd = sc.parallelize([('librarian', (1, [0, 0, 1, 0])), ('librarian', (1, [0, 1, 0, 0])),\
                      ('librarian', (1, [0, 1, 0, 0]))])

result = rdd.reduceByKey(lambda x, y: ( x[0] + y[0],\
                            [x[1][0]+y[1][0], x[1][1]+y[1][1], x[1][2]+y[1][2], x[1][3]+y[1][3] ] ))
print (result.collect())

To get output of movie with its genre and cast

Tag : mysql , By : TomL
Date : March 29 2020, 07:55 AM
this will help Like shadow said inner join and group_concat is what you need
Change your select statement to
 mo.title title
 , GROUP_CONCAT(DISTINCT p.people) people
  , GROUP_CONCAT(DISTINCT ge.genre) genre
  Movie mo
  inner join  movie_people mp 
    on mo.movie_id = mp.movie_id
  inner join people p 
    on mp.people_id = p.people_id
  inner join movie_genre mg
    on mg.movie_id = mp.movie_id
  inner join genre ge
    on ge.genre_id = mg.genre_id
 GrOUP By mo.movie_id,mo.title;
CREATE TABLE movie_people
    (`movie_id` int, `people_id` int)

INSERT INTO movie_people
    (`movie_id`, `people_id`)
    (1, 1),
    (1, 2),
    (2, 1),
    (2, 2)


    (`people_id` int, `people` varchar(14))

INSERT INTO `people`
    (`people_id`, `people`)
    (1, 'Dwayne Johnson'),
    (2, 'Jason Douglas')

CREATE TABLE `movie_genre`
    (`movie_id` int, `genre_id` int)

INSERT INTO `movie_genre`
    (`movie_id`, `genre_id`)
    (1, 1),
    (1, 3),
    (1, 4),
    (2, 1),
    (2, 2),
    (2, 4)

    (`genre_id` int, `genre` varchar(9))

    (`genre_id`, `genre`)
    (1, 'Action'),
    (2, 'Animation'),
    (3, 'Drama'),
    (4, 'Crime')

    (`movie_id` int, `title` varchar(6))

    (`movie_id`, `title`)
    (1, 'snitch'),
    (2, 'snitch')
title   people                          genre
snitch  Jason Douglas,Dwayne Johnson    Action,Crime,Drama
snitch  Dwayne Johnson,Jason Douglas    Animation,Crime,Action
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