Populating a Pandas DataFrame frome another DataFrame based on column names
Date : March 29 2020, 07:55 AM
To fix this issue I have a DataFrame of the following form: , You can just use the list to select them: In [44]:
cols = ['a', 'b', 'b', 'a', 'c']
df[cols]
Out[44]:
a b b a c
0 1 4 4 1 6
1 3 2 2 3 4
2 4 1 1 4 5
[3 rows x 5 columns]
|
Populating pandas dataframe using conditional group from another dataframe
Date : March 29 2020, 07:55 AM
This might help you I found one solution, perhaps not very elegant, and I'll check back in case anyone actually sees this and has a better one. I created a list of the column headers, then used iterrows to iterate through both each column and row in the column: batcol = pd.DataFrame(df1.columns)
batcol = batcol.iloc[6:-1]
batcol = batcol.reset_index(drop=True)
for index, row in batcol.iterrows():
for i, rows in df2.iterrows():
df2.loc[i, row] = df1[((df1['date'] < rows['date']) & (df1['team'] == rows['opp'])) == True].mean()[row].sum()
|
Python Pandas - Initialising and Populating a DataFrame
Tag : python , By : SachinJadhav
Date : March 29 2020, 07:55 AM
To fix this issue df = pd.DataFrame() produces an empty dataframe... But it's more empty than other empty dataframes. It has no index and no columns. df['First'] = 68 assigns the value of 68 to a column named 'First' for every index value. You'll note that the columns ['First', 'Second'] now exist. There were simply no index values for which to make the assignments of 68 and 157 df = pd.DataFrame(index=[1, 2, 3])
df['First'] = 68
df['Second'] = 157
print(df)
First Second
1 68 157
2 68 157
3 68 157
|
Populating a Pandas dataframe where index and column are values of another dataframe
Date : March 29 2020, 07:55 AM
hope this fix your issue I have a dataframe with columns ['ID', 'DATE', 'VALUE']. The way that the data I am sourcing comes in, I have many duplicate IDs, each of which has a duplicate price--so, for instance, the frame will come in with , We using combine_first+pivot_table newdf.combine_first(pd.pivot_table(df,index='Date',columns='ID',values='Value',aggfunc='sum'))
Out[442]:
a b
1/1/17 2.0 5.0
1/2/17 3.0 13.0
1/3/17 4.0 NaN
|
Python:Pandas Find the availability of a text inside a Pandas (Dataframe)
Date : March 29 2020, 07:55 AM
Hope that helps I am having two columns ColA ColB in pandas dataframe, I want to compare ColB with ColA if colA contains matching word with colB then i have to update colC as available. , Try the following: import pandas as pd
# Initialize example dataframe
data = [
["You can extract_insights on product reception", "insights"],
["user various sources like extract_insights etc.", "insights"],
["some other sourced mail by using signals from state art", "text"],
]
df = pd.DataFrame(data=data, columns=["ColA", "ColB"])
# Create column C with comparison results
df["ColC"] = [
"AVB" if (b in a) else "NAVB"
for (a, b) in zip(df["ColA"], df["ColB"])
]
print(df)
# Output:
# ColA ColB ColC
# 0 You can extract_insights on product reception insights AVB
# 1 user various sources like extract_insights etc. insights AVB
# 2 some other sourced mail by using signals from ... text NAVB
|