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Rub regex: matching a char except when after by another char


Rub regex: matching a char except when after by another char

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Rub regex: matching a char except when after by another char
Tag : java , By : Doug
Date : January 11 2021, 03:34 PM

This might help you I don't know how to retain the '.' delimiter after splitting, but I do know how to put them back. I also appears that the spaces that follow the delimiter should be removed.
The following regular expression will split ensuring that the '.' delimiter is not followed by a ')'. You may end up with an extra empty string, which can be removed:
import re

str = "This is a great (feeling.) thing. It's very interesting."
l = re.split(r'\.(?!\))', str)
# results are: ['This is a great (feeling.) thing', " It's very interesting", '']
if len(l[-1]) == 0:
    l.pop(-1) # get rid of last, empty string
l = [s.strip() + '.' for s in l] # get rid of leading and trailing spaces and add back delimiter
print(l)
['This is a great (feeling.) thing.', "It's very interesting."]

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regex matching char only if a specific char appeared before (conditional regex)


Tag : python , By : Anand
Date : March 29 2020, 07:55 AM
To fix the issue you can do First you must capture the opening parenthesis and then use a conditional pattern (I know the link is to php.net but I find it useful when referencing regexes, it also includes an example which exactly matches your case) that will only be applied if the first opening parenthesis is matched.
The pattern..
^(\()?0?(5[02-9])(?(1)\))-?(\d{7})$
(055)-5555555
(055)5555555 
0555555555
055)-5555555

Java regex : matching a char except when preceded by another char


Tag : java , By : Nosayaba
Date : March 29 2020, 07:55 AM
This might help you You need a negative lookbehind for that:
String.Split("(?<![\\\\]);");

Python/Regex - match char between two chars, with anything before or after the matching char


Tag : python , By : Bin
Date : March 29 2020, 07:55 AM
I wish this help you I'm trying to match a char within a subset of chars, where either side of the matching char could be anything. , Use
import re
s = '{{ SITE_AGGREGATE_SUBNET }}.3 remote-as {{ BGP-AS }}'
print([x.strip() for x in re.findall(r'{{(.*?)}}', s) if '-' in x])
// -> ['BGP-AS']
re.findall(r'{{\s*((?:(?!{{|}})[^-])*-.*?)\s*}}', s)

Regex for selecting upto char before char 'x' before char 'y'


Tag : java , By : Elwillow
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further Want to select text from first to the char before 'x' before 'y'. , You can use this regex:
^[^y]*(?=x)

What is this error? cannot convert 'char**' to 'char*' for argument '1' to 'char* strcpy(char*, const char*)


Tag : c , By : Mario Tristan
Date : March 29 2020, 07:55 AM
I wish this helpful for you
char * name[NAME_LEN];
 ^   ^  ^   ^
 |   |  |   |
 |   |  |  is an array of NAME_LEN
 |   | name
 |  pointers to
char
char name[NAME_LEN];
 ^    ^   ^
 |    |   |
 |    |  is an array of NAME_LEN
 |   name
char
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