Why this type is not an Interface?

Why this type is not an Interface?

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Why this type is not an Interface?
Tag : development , By : Nickolas
Date : January 11 2021, 03:34 PM

will be helpful for those in need An interface cannot have method implementations, and your type has five of them - Equals, GetHashCode, IEquatable<_>.Equals, IComparable<_>.CompareTo, and IComparable.CompareTo.
An interface is purely a set of method and properties. It's not like a base class, it cannot give the implementor some "default" implementations or base behavior or utility methods it anything like that.
type IKeyable<'A when 'A: equality and 'A :> IComparable> = 
    inherit IEquatable<'A>
    inherit IComparable<'A>
    abstract member Key : 'A
type Operation(id: Guid)
    inherit IKeyable<Guid>
    override this.Key = id
    member val Id = id

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If an class implements an interface, and is assigned to a variable with a type of that interface, what type is that obje

Tag : java , By : quicky
Date : March 29 2020, 07:55 AM
this will help The runtime type of the object remains Motor even when you assign it to the variable statically typed as the interface Measurable. The type defines the behavior, while the interface defines which methods you can call without a cast.

Convert from class to Interface with a generic type interface Interface<Interface>

Tag : chash , By : Aires
Date : March 29 2020, 07:55 AM
it fixes the issue In order to make it work, you need to make your generic interfaces covariant. But since ICollection is not covariant, it would require also changing the Children type to IReadOnlyCollection and remove the setters if you can afford that.
public interface ITaxonomyHasChildren<out TChild> : ITaxonomy where TChild : ITaxonomy
    IReadOnlyCollection<TChild> Children { get; }

public interface ITaxonomyHasParent<out TParent> : ITaxonomy where TParent : ITaxonomy
    TParent Parent { get; }
private void SelectedEntityChanged(ITaxonomy selectedEntity)
    CommonName = selectedEntity.CommonName;
    ScientificName = selectedEntity.ScientificName;

    Children = (selectedEntity as ITaxonomyHasChildren<ITaxonomy>)?.Children;
    Parent = (selectedEntity as ITaxonomyHasParent<ITaxonomy>)?.Parent;
class Taxonomy : ITaxonomy, ITaxonomyHasChildren<Taxonomy>, ITaxonomyHasParent<Taxonomy>
    public string CommonName { get; set; }
    public string ScientificName { get; set; }
    public Taxonomy Parent { get; set; }
    public List<Taxonomy> Children { get; set; } = new List<Taxonomy>();
    IReadOnlyCollection<Taxonomy> ITaxonomyHasChildren<Taxonomy>.Children => Children;

.NET Core Cast to interface with generic type parameter of type which implements interface

Tag : chash , By : Edwin
Date : March 29 2020, 07:55 AM
this will help Why don't you add a non-generic interface too:
interface IInterface { void Run(IParameter input); }

Create record from interface with return type as property type from original interface

Tag : typescript , By : tommy
Date : March 29 2020, 07:55 AM
it should still fix some issue I have an interface like , You can use a mapped type for this:
type Functionify<T> = { [K in keyof T]: () => T[K] }

Converting argument $1 type: unsupported type []interface {}, a slice of interface

Tag : postgresql , By : user185751
Date : March 29 2020, 07:55 AM
may help you . Wrap the slice with pq.Array. Change IN ($1) to = any($1) so the array value can be used.
Here's the code:
    stm := `SELECT
        CASE WHEN TRIM(UP.first_name || ' ' || UP.last_name) = '' THEN U.id :: TEXT ELSE UP.first_name || ' ' || UP.last_name END
        ) as avatar_name,
    users AS U
        JOIN user_profiles UP ON UP.user_id = U.id
        U.id = any($1);`
    rows, err := postgresql.Instance.Query(stm, pq.Array(userIDs))
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