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why datetime.now() and constructed datetime using all fields(like year,month...) of now has big timedelta?


why datetime.now() and constructed datetime using all fields(like year,month...) of now has big timedelta?

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why datetime.now() and constructed datetime using all fields(like year,month...) of now has big timedelta?
Tag : python , By : ap.
Date : January 11 2021, 03:34 PM

This might help you That output is correct. It's telling you that, in order to make testTime equal to now, you'd need to subtract one day from testTime (that's the -1 day), then add back 23 hours, 59 minutes, 59 seconds, and 106000 microseconds. Effectively, that's saying "testTime is 894000 microseconds before now", which is correct; you truncated off the microseconds, makingtestTime ever-so-slightly earlier than now.
Are you sure you didn't flip your operands? print(now - testTime) would output 0:00:00.894000 which is probably the output you were looking for.

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Symfony - search table by month, year for datetime fields


Tag : development , By : user119605
Date : March 29 2020, 07:55 AM
Hope this helps Why dont you try to create 2 date and check if that date is between them, for example (2010-01-01 >= $date && 2010-01-31 <= $date ). If so, then your in range and all coincidences will appear.
If you absolutely have to check for month and year i recommend using functions like YEAR(date) = $yourDate and Month(date) = $yourMonth, this functions should go along with a CUSTOM criteria and could look like:
$criterias->addCriteria(TablePeer::DATE_ATTRIBUTE,"YEAR(". TablePeer::DATE_ATTRIBUTE .") = $year",Criteria::CUSTOM);
$criterias->addCriteria(TablePeer::DATE_ATTRIBUTE,"MONTH(". TablePeer::DATE_ATTRIBUTE .") = $month",Criteria::CUSTOM);

Counting year and month entries from datetime fields


Tag : mysql , By : user169463
Date : March 29 2020, 07:55 AM
Hope this helps You will need two separate queries, one for subscriptions and other for unsubscriptions.
SELECT COUNT(*), YEAR(fDateConfirmed), MONTH(fDateConfirmed) FROM tSubscriber GROUP BY YEAR(fDateConfirmed), MONTH(fDateConfirmed)
SELECT COUNT(*), YEAR(fDateUnsubscribed), MONTH(fDateUnsubscribe ) FROM tSubscriber GROUP BY YEAR(fDateUnsubscribed), MONTH(fDateUnsubscribed)

Wanted: DateTime.TryNew(year, month, day) or DateTime.IsValidDate(year, month, day)


Tag : chash , By : joshski
Date : March 29 2020, 07:55 AM
seems to work fine There is not a static function IsValidDate() so you have to write it by yourself, first naive implementation may be:
public static bool IsValidDate(int year, int month, int day)
{
    if (year < DateTime.MinValue.Year || year > DateTime.MaxValue.Year)
        return false;

    if (month < 1 || month > 12)
        return false;

    return day > 0 && day <= DateTime.DaysInMonth(year, month);
}
public static DateTime? TryNew(int year,
                               int month,
                               int day,
                               Calendar calendar)
{
    if (calendar == null)
        calendar = new GregorianCalendar();

    if (year < calendar.MinSupportedDateTime.Year)
        return null;

    if (year > calendar.MaxSupportedDateTime.Year)
        return null;

    // Note that even with this check we can't assert this is a valid
    // month because one year may be "shared" for two eras moreover here
    // we're assuming current era.
    if (month < 1 || month > calendar.GetMonthsInYear(year))
        return null;

    if (day <= 0 || day > DateTime.DaysInMonth(year, month))
        return null;

    // Now, probably, date is valid but there may still be issues
    // about era and missing days because of calendar changes.
    // For all this checks we rely on DateTime implementation.        
    try
    {
        return new DateTime(year, month, day, calendar);
    }
    catch (ArgumentOutOfRangeException)
    {
        return null;
    }
}
return TryNew(year, month, day) ?? DateTime.MinValue;

Why does datetime.datetime.now() - datetime.datetime.now() equal to datetime.timedelta(-1, 86399, 999974)?


Tag : python , By : Tim Tyrrell
Date : March 29 2020, 07:55 AM
To fix the issue you can do Consider the following snippet: , See the datetime.timedelta documenation:
>>> from datetime import timedelta
>>> d = timedelta(microseconds=-1)
>>> (d.days, d.seconds, d.microseconds) (-1, 86399, 999999)
>>> import datetime
>>> td = datetime.datetime.now() - datetime.datetime.now()
>>> print(td)
-1 day, 23:59:59.999988
>>> td
datetime.timedelta(-1, 86399, 999988)
>>> td.days
-1
>>> td.seconds
86399
>>> td.microseconds
999988
>>> (24 * 60 * 60)  # 1 day in seconds
86400
>>> (24 * 60 * 60) - td.seconds
1
>>> 1000000 - td.microseconds
12

Django - Need datetime fields that can handle only year, or year and month values


Tag : python , By : T11M
Date : March 29 2020, 07:55 AM
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