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How to check if a character is a not a part of number or URL in string?


How to check if a character is a not a part of number or URL in string?

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How to check if a character is a not a part of number or URL in string?
Tag : python , By : Vodkat
Date : January 11 2021, 03:32 PM

this one helps. You should only really have to check to see if the character after the delimiter is a white space to tell if it's not at the end of the sentence. No re needed.
delimiters = ['!', '?', '.']
def is_delimiter(char, next_char):
    if char in delimiters:
        if next_char is not None:
            if next_char == ' ':
                return True
        else:
            return True
    return False

text = "Hello. I'll come back on 12.09."

for i in range(0, len(text)):
    char = text[i]

    j = i+1

    if j < len(text):
        next_char = text[j]
    else:
        next_char = None

    print(char, is_delimiter(char, next_char))


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How to separate character and number part from string


Tag : chash , By : nonkelhans
Date : March 29 2020, 07:55 AM
this will help E.g., I would like to separate: , I have used bniwredyc's answer to get Improved version of my routine:
    private void demo()
        {
            string cell = "ABCD4321";
            int row, a = getIndexofNumber(cell);
            string Numberpart = cell.Substring(a, cell.Length - a);
            row = Convert.ToInt32(Numberpart);
            string Stringpart = cell.Substring(0, a);
        }

        private int getIndexofNumber(string cell)
        {
            int indexofNum=-1;
            foreach (char c in cell)
            {
                indexofNum++;
                if (Char.IsDigit(c))
                {
                    return indexofNum;
                }
             }
            return indexofNum;
        }

select part of a string after certain number of special character


Tag : r , By : liquidx
Date : March 29 2020, 07:55 AM
I hope this helps you . I have a data.table with a column , If k is the number of fields to keep:
k <- 2
DT[, V1 := do.call(paste, c(read.table(text=V1, fill=TRUE, sep="_")[1:k], sep = "_"))]
library(data.table)

DF <- data.frame(V1 = c("a_b_c_las_poi", "a_b_c_kiosk_pran", "a_b_c_qwer_ok"),
   stringsAsFactors = FALSE)
DT <- as.data.table(DF)

String having a text part and number part separated through match function does not increment number part by 1 after 8


Tag : javascript , By : lifchicker
Date : March 29 2020, 07:55 AM
wish of those help The OP reports that parseInt('00008'); returns 0 (zero) instead of decimal 8 (eight). The reason is that the leading zeros are causing parseInt to assume base 8 (instead of base 10).
Solution:

Check if part of a string is a number


Tag : php , By : Revision17
Date : March 29 2020, 07:55 AM
this one helps. I don't know exactly what kind of data you will receive, but it looks like you can use a regular expression. For example, assume that $uri is the string and you want a number in the format: "/room/NUMBER/messages". You can use:
preg_match("~/room/([0-9]+)/messages~", $uri, $matches);
if(isset($matches[1])) {
  $roomnumber = $matches[1];
  // do what you want
} else {
  // There is no room number
}

Check if any part of a string input is not a number


Tag : java , By : foxthrot
Date : March 29 2020, 07:55 AM
it should still fix some issue I would personally create my own helper methods for this, instead of using an external library such as Apache (unless you already plan on using the library elsewhere in the project).
Here is an example of what it could look like:
public static void main(String[] arguments) {
    String time = "10:50:45";
    String [] arr = time.split(":");

    if (containsNumbers(arr)) {
        System.out.println("Time contained a number!");
    } 
    //You can put an else if you want something to happen when it is not a number
}

private static boolean containsNumbers(String[] arr) {
    for (String s : arr) {
        if (!isNumeric(s)) {
            return false;
        }
    }
    return true;
}

public static boolean isNumeric(String str) {
    return str.matches("-?\\d+(.\\d+)?");
}
String time = "sd:fe:gbdf";
returns false

String time = "as:12:sda";
returns false

String time = "10:50:45";
returns true
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