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How to convert a navigation list with depth levels to a parent-child flat list?


How to convert a navigation list with depth levels to a parent-child flat list?

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How to convert a navigation list with depth levels to a parent-child flat list?
Tag : python , By : wraith
Date : January 11 2021, 03:32 PM

this one helps. I have these lists in python:
docs_id = ['10','20','21','22','30','31','32','40','41','42','421','422']

text = ['1. Chapter', '2. Chapter', '2.1 Chapter',
        '2.2 Chapter','3. Chapter', '3.1 Chapter','3.2 Chapter',
        '4. Chapter','4.1. Chapter','4.2 Chapter',
        '4.2.1 Chapter','4.2.2 Chapter']

depth= [1, 1, 2, 2, 1, 2, 2, 1, 2, 2, 3, 3]

currentdepth = 1

tree = []

current_doc_id = 0

for i, value in enumerate(text):

    newdepth = depth[i]
    doc_id = docs_id[i]
    title = value


    if newdepth > currentdepth:

        global current_doc_id
        current_doc_id =  docs_id[i-1]
        tree.append([doc_id, title, int(current_doc_id)])

        currentdepth += 1
    elif newdepth == currentdepth:
        tree.append([doc_id, title, int(current_doc_id)])
    else:
        current_doc_id=0
        tree.append([doc_id, title, int(current_doc_id)])
        while newdepth>currentdepth:
            currentdepth -=1
        currentdepth-=1





for i in tree:
    print(i)

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Entity Framework 6: Adding child object to parent's list vs. setting child's navigation property to parent


Tag : chash , By : user180941
Date : March 29 2020, 07:55 AM
Hope this helps Yes, the two approaches are interchangeable. This allows you to create and save your object graph to the database from either the perspective of the MailServer or the MailDomain.
If you do code-first, you have the option of removing the properties and mappings if they're not needed.

XML parent child structure from flat list


Tag : vba , By : Anand
Date : March 29 2020, 07:55 AM
Any of those help Something like this might work for you. Has no error checking on the levels (will break if there's a "level 4" with no previous "level 3").
Sub Tester()

    Dim d, doc, root, lvl As Long, r, el, id
    Dim parents(0 To 20)  'handle up to 20 levels...

    Set doc = New MSXML2.DOMDocument
    Set root = doc.createElement("root")
    doc.appendChild root

    Set parents(0) = root 'Parent node for all "Level 1" nodes...

    d = Range("a1").CurrentRegion.Value

    For r = LBound(d, 1) To UBound(d, 1)

        lvl = CLng(Split(d(r, 1), " ")(1)) 'get level

        Set el = doc.createElement("section")
        el.setAttribute "ident", d(r, 2)

        parents(lvl - 1).appendChild el
        Set parents(lvl) = el ' Make this the current Parent node for
                              '   any nodes directly below

    Next r

    Debug.Print PrettyPrintXML(doc.XML)

End Sub

React Native navigation for child components in flat list


Tag : javascript , By : Mena
Date : March 29 2020, 07:55 AM
wish of those help Im pretty new in React Native (and Javscript) and im trying to understand react native navigation. , You can do it as following.
    render() {
        return (
        //    <List>
                <FlatList
                    data={this.state.data}
                    renderItem={({ item }) => (


                        <CardComponent
                        navigation={this.props.navigation}
                        eventname={'Halloween'}
                        eventveranstalter={'park'}
                        eventuhr={'17:00'}
                        eventort={'berlin'}
                        eventimage={'http://whatstonightapp.com/wp-content/uploads/2016/12/background_light-1.jpg'}
                        eventtag1={'party'}
                        eventtag2={'music'}
                        eventtag3={'dance'}
                        >

                        </CardComponent>

                    )}

Need to convert list of data into list of list based on parent child relationship


Tag : java , By : Adam
Date : March 29 2020, 07:55 AM
it should still fix some issue For representing the tree structure, I have used an ArrayList, where the index of the node is equal to its index in the array + 1. If you have a sparse tree/some indices might be missing, use an equivalent approach with a map instead.
Solution using Java 8 stream API:
public static void main( String[] args ) {
        List<ResponseData> responseDataList = Arrays.asList(
            new ResponseData( 1, -1 ),  // changed null to -1 as null can't be a map key
            new ResponseData( 2, 1 ),
            new ResponseData( 3, 1 ),
            new ResponseData( 4, 1 ),
            new ResponseData( 5, 2 ),
            new ResponseData( 6, 2 ),
            new ResponseData( 7, 3 ),
            new ResponseData( 8, 3 ),
            new ResponseData( 9, 4 ),
            new ResponseData( 10, 4 ),
            new ResponseData( 11, 5 ),
            new ResponseData( 12, -1 ),
            new ResponseData( 13, 12 )
        );
        final Map<Integer, List<ResponseData>> map = responseDataList.stream()
                .collect( Collectors.groupingBy( o -> getLevel( responseDataList, o, 0 ) ) );
        System.out.println( map );
        // To convert the Map to a List of Lists:
        System.out.println( new ArrayList<>( map.values() ));
    }

    private static int getLevel(List<ResponseData> nodes, ResponseData responseData, int level) {
        if( responseData.parent == -1 ) {
            return level;
        } else {
            return getLevel( nodes, nodes.get( responseData.parent - 1 ), level + 1 );  // -1 to adjust index
        }
    }

    private static final class ResponseData {
        public int id;
        public int parent;

        public ResponseData( int id, int parent ) {
            this.id = id;
            this.parent = parent;
        }

        @Override
        public String toString() {
            return String.format( "{id: %d, parent: %d}", id, parent );
        }
    }

convert a flat list into a tree with limited number of nodes per depth


Tag : java , By : Nick Pegg
Date : March 29 2020, 07:55 AM
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