How to remove nested empty objects in JavaScript?

How to remove nested empty objects in JavaScript?

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How to remove nested empty objects in JavaScript?
Tag : javascript , By : LucaN
Date : January 11 2021, 03:32 PM

this will help instead of checking for null ( obj[k] != null ) , check for Object.values().length ( or Object.keys().length) :
const stocklevels = {
  coats: {
    browncoat: ["L", "M", "S"]
  neclace: {},
  earrings: {
    diamond: "Y",
    ruby: "Y"
  shoes: {},
  bags: {}

let newObj = Object.keys(stocklevels).reduce((acc, curr) => {  
  if(Object.keys(stocklevels[curr]).length > 0)
    acc[curr] = stocklevels[curr]
  return acc;
}, {});

const obj ={ 
  a :{
    b :{
      c :{} // won't remove this
  d : {
    x : 'x'

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How do you recursively remove nested objects that contain an empty array?

Tag : javascript , By : keird
Date : March 29 2020, 07:55 AM
This might help you You can remove the elements in your response with empty arrays with this code.
It cycles through the top level, looking for any empty arrays and removing them. Any objects it finds, it recurses into to also remove empty arrays in them:
// make sure the ES5 Array.isArray() method exists
if(!Array.isArray) {
  Array.isArray = function (arg) {
    return Object.prototype.toString.call(arg) == '[object Array]';

function removeEmptyArrays(data) {
    for (var key in data) {
        var item = data[key];
        // see if this item is an array
        if (Array.isArray(item)) {
            // see if the array is empty
            if (item.length == 0) {
                // remove this item from the parent object
                delete data[key];
        // if this item is an object, then recurse into it 
        // to remove empty arrays in it too
        } else if (typeof item == "object") {

var jsonOBJ = {};
jsonOBJ = jQuery.parseJSON(data);

How do I test if a Javascript object has only empty objects at the last nested level?

Tag : javascript , By : negonicrac
Date : March 29 2020, 07:55 AM
Hope this helps An object is empty if it's, well, an object, and every one of its keys is in turn an empty object.
function empty(o) {

  function isObject()      { return o && o.constructor === Object; }
  function keyEmpty(key)   { return empty(o[key]; }
  function everyKeyEmpty() { return Object.keys(o) . every(keyEmpty); }

  return isObject() && everyKeyEmpty();

Remove objects with empty values from array / Javascript

Tag : javascript , By : Munir
Date : March 29 2020, 07:55 AM
To fix the issue you can do I have an array of objects: , IMHO, you are looking for something like this:
var arr = [{id:0, value: 'zero'}, {id:1, value: 'one'}, {id:2, value: ''}];

var filteredArr = arr.filter(obj => obj.value != '')

Remove empty & null values from nested object (ES6) - Clean nested Objects

Tag : javascript , By : Tornike
Date : March 29 2020, 07:55 AM
wish of those help You could take an straight forward approach by iterating the key/value pairs of the object and iterate nested iterable objects first and then delete the unwanted keys.
function clean(object) {
        .forEach(([k, v]) => {
            if (v && typeof v === 'object') {
            if (v && typeof v === 'object' && !Object.keys(v).length || v === null || v === undefined) {
                if (Array.isArray(object)) {
                    object.splice(k, 1);
                } else {
                    delete object[k];
    return object;

var object = { a: "string not empty", b: { c: "string not empty" }, d: { e: false, f: 0, g: true, h: 10 }, i: { j: 0, k: null }, l: { m: null }, n: { o: 1, p: "string (not empty)", q: {} }, r: [{ foo: null }] };

.as-console-wrapper { max-height: 100% !important; top: 0; }

Remove duplicates from nested map objects javascript

Tag : javascript , By : user169463
Date : March 29 2020, 07:55 AM
Hope that helps The simple way is that create an array in which you push the elements that are printed.And before printing the other check if its present in array or not.
const arr = [];
    this.state.rows.map((qc) =>
        qc.BinsByDayByOrchardsQCs.map((qc2) =>
            qc2.BinsByDayByOrchardsQCsDefects.map((qc3) =>
              {!arr.includes(qc3.Defect) && arr.push(qc3.Defect) &&
                (<div className="row table">
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