How to find index deep in javascript array and return other part of array?
Date : March 29 2020, 07:55 AM
I wish did fix the issue. If you need to find many objects, you can build a lookup table. Iterate over your collection of main objects, and store them in an key-value-map (simple object) by their identifier: var mainsByKid = {}; // if the keys are integers (and not sparse), use an array
for (var i=0; i<mains.length; i++) {
var main = mains[i],
key = main.properties.kid; // must be unique
mainsByKid[key] = main;
}
mainsByKid[1];
|
How to find every occurrence of a target value in array and return a new array containing the indexes for these values?
Tag : java , By : Steve M
Date : March 29 2020, 07:55 AM
will be helpful for those in need You are never incrementing indexNum, it always remains at 0 and the array keeps on writing the values at this same index. I think you should have this expression there: newArray[indexNum++] = i;
|
PHP: Find string in Multi-dimensional array or return empty array keys?
Tag : php , By : Gilmar Souza Jr.
Date : March 29 2020, 07:55 AM
will be helpful for those in need Your JOIN to the empty beds query is leaving out empty values. I suggest you use a subquery to generate a complete list of room_category values. select distinct room_category
from room_category
select a.room_category,
group_concat(b.room_name ORDER BY b.room_name) vacancies
from (select distinct id, room_category from room_category) a
left join
(select rct.room_category AS room_category,
rn.room_name
from room_category rct
left join room_name rn on rn.room_category = rct.id
left join patient_detail pd on rn.id = pd.bed_type
and (isnull(pd.discharge_date) or now()
between pd.admission_date and pd.discharge_date)
where isnull(pd.id)
order by rct.room_category, rn.room_name
) b on a.room_category=b.room_category
group by a.room_category
order by a.room_category
|
Find duplicate objects in array and return new array of object with number of duplicates as a new property
Date : March 29 2020, 07:55 AM
it fixes the issue I think you'd be best suited by creating a helper object. A helper object will initially be empty, but will become populated slowly by what you're reading through. I'm going to assume that the keys in your array are consistent. const keys = ["Name","Type"]
var counterObj = {}
let keyForCounterObj
arrayOfObjects.forEach((obj)=>{
keyForCounterObj = ''
keys.forEach((key)=>{
keyForCounterObj += String(obj[key])
}
if(counterObj[keyForCounterObj]){
counterObj[keyForCounterObj].times ++
}else{
counterObj[keyForCounterObj] = {
...obj,
times:1
}}}
counterObj = {
AppleFruit: {
Name:"Apple",
Type:"Fruit",
times:3,
},
CarrotVegetable:{
Name:"Carrot",
Type:"Vegetable",
times:4,
}
}
let newArrayOfObjects = []
const counterObjKeys = Object.keys(counterObj)
counterObjKeys.forEach((key)=>{
newArrayOfObjects.push(counterObj[key])
}
|
Cakephp How to set find() to return blank array instead of empty array when no result matched
Date : March 29 2020, 07:55 AM
|