How to extract year or month,day from oracle function without using sub-query?

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How to extract year or month,day from oracle function without using sub-query?
How to select results between two dates or by single year/month/day in oracle? (to_date, extract,sysdate)
Extract month and year from date in oracle
Extract month and year from date in oracle ORA-01722: Nombre non valide
Extract data from starting month and year to end month and year not working python pandas
Python - Extract year and month from a single column of different year and month arrangements

How to extract year or month,day from oracle function without using sub-query?

Tag : sql , By : Dave

Date : January 11 2021, 03:32 PM

may help you . I cannot reproduce your problem in version 19c, or else I don't understand it. Anyway, three remarks:
1) If your START_TIME is really a string, that is just not a good idea at all. Use real DATE or TIMESTAMP datatypes. In your shoes, I would replace both columns by one column with a TIMESTAMP WITH TIME ZONE datatype. As it is, you cannot sort properly by date because of the time zone offsets.

with data(START_TIME, UTC_TIME_CODE_OFFSET) as (
  select '20001112012345', '+02' from dual
)
select
to_timestamp_TZ(
  START_TIME || substr(UTC_TIME_CODE_OFFSET,1,3),
  'YYYYMMDDHH24MISSTZH'
)  at local as local_ts,
to_char(
  to_timestamp_TZ(
    START_TIME || substr(UTC_TIME_CODE_OFFSET,1,3),
    'YYYYMMDDHH24MISSTZH'
  )
  ,'DD'
) as to_char_day,
extract(
  day from
  to_timestamp_TZ(
    START_TIME || substr(UTC_TIME_CODE_OFFSET,1,3),
    'YYYYMMDDHH24MISSTZH'
  )
) as extract_day
from data;

LOCAL_TS                                   TO_CHAR_DAY EXTRACT_DAY   
2000-11-12 00:23:45,000000000 EUROPE/PARIS 12          11

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How to select results between two dates or by single year/month/day in oracle? (to_date, extract,sysdate)

Tag : oracle , By : James Dio

Date : March 29 2020, 07:55 AM

will be helpful for those in need The Oracle DATE type stores a date+time down to the nearest second - so if you say f.data_entrega = '10.01.24' it will not match a record where f.data_entrega is 10.01.24 at 6am. SYSDATE, similarily, returns the current time as well as today's date.
If you want your function to match on the date portion only (i.e. ignore any time values), you may need to change the function:

select f.total_enc_fornec into v_total_enc
from fornecimento f
where f.data_entrega between TRUNC(init_date) and TRUNC(final_date) + 0.99999;

Extract month and year from date in oracle

Tag : sql , By : quasarkitten

Date : March 29 2020, 07:55 AM

To fix the issue you can do If the field is already a date column, you can simply cast it to the format you want:

select ID_NO,CHECKED_DATE,ltrim(TO_CHAR(CHECKED_DATE,'mm-yyyy'),'0') AS A from Doctor_Checkup;

select ID_NO,CHECKED_DATE,ltrim(TO_CHAR(TO_DATE(CHECKED_DATE,'dd/mm/yyyy'),'mm-yyyy'),'0') AS A from Doctor_Checkup;

Extract month and year from date in oracle ORA-01722: Nombre non valide

Tag : oracle , By : David Marchant

Date : March 29 2020, 07:55 AM

wish of those help '01/10/2008' is a string, not a date. There are four to_char() functions which take different argument types, and (presumably because of implicit conversion precedence) you're actually ending up calling to_char(number), not the (date) version you intended.
That means you're effectively doing TO_CHAR(TO_NUMBER('01/10/2008'), 'MON-YY'), and it's the implicit TO_NUMBER('01/10/2008') that is throwing the ORA-01722.

select TO_CHAR(TO_DATE('01/10/2008', 'DD/MM/YYYY'), 'MON-YY') from dual;

TO_CHA
------
OCT-08

alter session set NLS_DATE_LANGUAGE='FRENCH';

select TO_CHAR(TO_DATE('01/07/2018', 'DD/MM/YYYY'), 'MON-YY') from dual;

TO_CHAR(
--------
JUIL.-18

select TO_CHAR(TO_DATE('01/07/2018', 'DD/MM/YYYY'), 'MON-YY',
  'NLS_DATE_LANGUAGE=ENGLISH') from dual;

TO_CHA
------
JUL-18

Extract data from starting month and year to end month and year not working python pandas

Tag : python , By : 3NZ0

Date : March 29 2020, 07:55 AM

To fix the issue you can do df , Change your loops to

for y in range(2010, 2015):
    for x in range(1, 13):
        df2 = df[df["order_date"].dt.month.eq(x) & df["order_date"].dt.year.eq(y)]
    print("Data for period", x, y, "is\n", df2)

Python - Extract year and month from a single column of different year and month arrangements

Tag : python , By : anov

Date : September 26 2020, 01:00 AM

I wish did fix the issue. You can make use of the extract dataframe string method to split the date strings up. Since the year can precede or follow the month, we can get a bit creative and have a Year1 column and Year2 columns for either position. Then use np.where to create a single Year column pulls from each of these other year columns.
For example:

import numpy as np

split_dates = df["Date"].str.extract(r"(?P<Year1>\d+)?-?(?P<Month>\w+)-?(?P<Year2>\d+)?")

split_dates["Year"] = np.where(
    split_dates["Year1"].notna(),
    split_dates["Year1"],
    split_dates["Year2"],
)

split_dates = split_dates[["Year", "Month"]]

  Year Month
0   18   Jan
1   18   Jan
2   18   Feb
3   18   Feb
4   17   Oct
5   17   Oct

pd.merge(df, split_dates, how="inner", left_index=True, right_index=True)

     Date  Quantity Year Month
0  18-Jan      3476   18   Jan
1  18-Jan        20   18   Jan
2  18-Feb       789   18   Feb
3  18-Feb       409   18   Feb
4  Oct-17        81   17   Oct
5  Oct-17       640   17   Oct