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Algorithm for ‘spreading` sum in Hash


Algorithm for ‘spreading` sum in Hash

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Algorithm for ‘spreading` sum in Hash
Tag : ruby , By : B3CFT
Date : January 11 2021, 03:32 PM

I hope this helps you . This solution could be a starting point, I didn't test for avoiding infinite loop:
banknotes = { 5 => 6, 10 => 7, 20 => 8, 50 => 9 }
amount = 335

min = banknotes.keys.min
init_avg = amount / banknotes.keys.sum # calculate the initial average
result = banknotes.transform_values { init_avg } # initialize with average
delta = amount - result.sum { |k,v| k * v }

if delta > 0 # start distribution
  loop do
    banknotes.keys.reverse_each do |val|
      if delta - val >= 0 and result[val] + 1 < banknotes[val]
        delta -= val
        result[val] += 1
      end
    end
    break if delta < min
  end
end

result
#=> {5=>3, 10=>4, 20=>4, 50=>4}

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why should a good hash algorithm not allow attackers to find two messages producing the same hash?


Tag : security , By : warttack
Date : March 29 2020, 07:55 AM
may help you . Yes, it's inevitable that there will be collisions when mapping a long message onto a shorter hash, as the hash cannot contain all possible values of the message. For the same reason you cannot 'invert' the hash to uniquely produce either Beowulf or The Hobbit - but if you generated every possible text and filtered out the ones that had your particular hash value, you'd find both texts (amongst billions of others).
The article is saying that it should be hard for an attacker to find or construct a second message that has the same hash value as a first. Cryptographic hash functions are often used as proof that a message hasn't been tampered with - if even a single bit of data flips then the hash value should be completely different.

Is it possible to use label spreading scikit algorithm on edgelist?


Tag : python , By : user171752
Date : March 29 2020, 07:55 AM
wish of those help To use Label Spreading you should follow these steps: 1. create a vector of labels (y), where all the unlabeled instances are set to -1. 2. fit the model using your feature data (X) and y. 3. create predict_entropies vector using stats.distributions.entropy(yourmodelname.label_distributions_.T) 4. create an uncertainty index by sorting the predict_entropies vector. 5. send the samples of lowest certainty for label query.
I hope this framework will help you get started.

A* algorithm current node spreading outwards instead of one direction


Tag : java , By : Tim
Date : March 29 2020, 07:55 AM
like below fixes the issue The yellow circle indicates the starting node and the red circle is indicating the goal node. I can't understand why my current node is spreading outwards instead of the image below where the node is just going straight into the goal. , I think you have a problem to get the lowestcost:
private Node getLowestFCost(List<Node> open) {
    int lowestCost = 0;
    int index = 0;
    for (int i = 0; i < open.size(); i++) {
        if (open.get(i).fCost <= lowestCost) {
            lowestCost = open.get(i).fCost;
            index = i;
        }
    }
    return open.get(index);
}

Leveinshtein and hash - finding one hash algorithm that results in correlation (closer distance)


Tag : python , By : Zinovate
Date : March 29 2020, 07:55 AM
wish help you to fix your issue The solution I wanted is LSH: https://en.wikipedia.org/wiki/Locality-sensitive_hashing
It solves the question, I posed. It's a technique used in Information Retrieval to find duplicates documents or web pages. Thus I can use the same to compare my two strings and get their similarity index.

How is Hash in Ruby implemented internally? What data structure/algorithm Hash is using?


Tag : ruby , By : Dean
Date : March 29 2020, 07:55 AM
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