Java getting every second element from array list and using it as value for hash map

Java getting every second element from array list and using it as value for hash map

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Java getting every second element from array list and using it as value for hash map
Tag : java , By : kema
Date : December 02 2020, 10:46 PM

hope this fix your issue I have the following text file :
public Map<String, String> Payload1() throws IOException {
    Scanner sc = new Scanner (new File("src/boot/Payload1.txt"));
    Map<String, String> fileMap = new LinkedHashMap<String, String>();
    int counter = 1;
    String key = "";
    while (sc.hasNextLine()) {
        if(counter % 2 != 0) {
            key = sc.nextLine();
        }else {
            fileMap.put(key, sc.nextLine());
    return fileMap;
public Map<String, String> getFileMap(List<String> list){
    Map<String, String> fileMap = new LinkedHashMap<String, String>();
    String key = "";
    for(int x = 0; x < list.size(); x++) {
        if((x + 1 ) % 2 != 0) {
            key = list.get(x);
        }else {
            fileMap.put(key, list.get(x));
    return fileMap;

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How to check if element in groovy array/hash/collection/list?

Tag : arrays , By : snk
Date : March 29 2020, 07:55 AM
help you fix your problem .contains() is the best method for lists, but for maps you will need to use .containsKey() or .containsValue()

Selecting single hash from array where one hash element has the highest value

Tag : ruby , By : Pierre LeBoo
Date : March 29 2020, 07:55 AM
To fix this issue From the following array of hashes, how can I select a single hash where timestamp has the highest value? , Here you can see:
 data.max_by{|e| e["timestamp"] }
 # >> {"id"=>2, "timestamp"=>1383314386, "data"=>"64ed2ed9-763d-443f-a74e-e7f10cbe783e"}

In Perl, how can I access a hash array element, that is itself another hash array?

Tag : perl , By : Techspirit
Date : March 29 2020, 07:55 AM
like below fixes the issue You didn't declare %thisDevice hash and $thisDevice hashref is completely another variable.

Java 1D array list collection .contains or Hash-Map.containsKey speed

Tag : java , By : kgw
Date : March 29 2020, 07:55 AM
Any of those help You can find details on how each is implemented in the java docs. I believe ArrayList will do a linear search. So HashMap is most likely better.

Java Hash map / Array List Count distinct values

Tag : java , By : Ricardo
Date : March 29 2020, 07:55 AM
will be helpful for those in need You could store a Setof productIds per clientId, and just take the size of that. As a Set does not allow duplicate values, this will effectively give you the distinct number of productIds.
Also, I recommend that you give your variables meaningful name instead of col2, k, map... This will make your code more readable.
Map<String, Set<String>> distinctProductsPerClient = new HashMap<String, Set<String>>();
// Process each CSV file line which is now contained within
// the linesList list Array
// Start from 1 to skip the first line
for (int i = 1; i < linesList.size(); i++) {
    String line = linesList.get(i);
    String[] data = line.split(csvSplitBy);
    String productId = data[1];
    String clientId = data[2];
    String date = data[3];

    // Determine if Column 4 has the desired date
    // and count the values
    if (date.contains("10/12/2017"))  {
        if (!distinctProductsPerClient.containsKey(clientId)) {
            distinctProductsPerClient.put(clientId, new HashSet<>());


for (final String clientId : distinctProductsPerClient.keySet()) {
    System.out.println(clientId + ": " + distinctProductsPerClient.get(clientId).size());
private static class OrderData {

    private final String productName;
    private final String productId;
    private final String clientId;
    private final String date;

    public OrderData(String csvLine) {

        String[] data = csvLine.split("\t");

        this.productName = data[0];
        this.productId = data[1];
        this.clientId = data[2];
        this.date = data[3];


    public String getProductName() {
        return productName;

    public String getProductId() {
        return productId;

    public String getClientId() {
        return clientId;

    public String getDate() {
        return date;
Map<String, Set<String>> distinctProductsPerClient2 = linesList.stream()
        .collect(groupingBy(OrderData::getClientId, mapping(OrderData::getProductId, toSet())));
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