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After navigating to each link in the webpage,how to get list of all forms with method =post using selenium java


After navigating to each link in the webpage,how to get list of all forms with method =post using selenium java

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hop of those help? Using regular expressions for parsing HTML is not the best idea, there are way better locator strategies which can talk to DOM as it's a structured information.
For example you can go for XPath:
List<WebElement> forms driver.findElements(By.xpath("//form[@method='post']"));

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How to login to a webpage and get its html code with Java, when it uses post method for logging in?


Tag : java , By : Ed.
Date : March 29 2020, 07:55 AM
hop of those help? Are you using something like apache commons http. You can use post method.

Link to Webpage using Post Method


Tag : development , By : tayles
Date : March 29 2020, 07:55 AM
hop of those help? Ok so i just realized my mistake,really a silly one. in the link to Register Form page in My Login Form Page i didnt add the extension ".html" so tomcat was trying to find a Servlet name Register rather than a link to Register.html

Tag : java , By : Willem van Schevikho
Date : March 29 2020, 07:55 AM
seems to work fine I have discovered that when I update webpage the consequences of profile links is breaking down. So, the decision was to open profile link in new window. Do some action and close it. As guys above said using two loops was stupid decision. This code works for me perfect:
for(WebElement link : driver.findElements(By.xpath("//img[@alt='Online Now!']/../..//a"))){             
            String originalWindow =driver.getWindowHandle();
            System.out.println("Original handle is: "+ originalWindow);
//open link in new window
            act.contextClick(link).perform();
            act.sendKeys("w").perform();

            Thread.sleep(4000);
            for (String newWindow : driver.getWindowHandles())
            {
            driver.switchTo().window(newWindow); 
            System.out.println("NOW THE CURRENT Handle is: "+ newWindow);
            }
            Thread.sleep(2000);
//here write a message              
            driver.close();
            driver.switchTo().window(originalWindow);
}
List<WebElement> allLinks = driver.findElements(By.xpath("//img[@alt='Online Now!']/../..//a"));
//have found links of all online profiles
System.out.println(allLinks.size());
for (WebElement link : allLinks)
{
    String originalWindow =driver.getWindowHandle();
            System.out.println("Original handle is: "+ originalWindow);
//open link in new window
            act.contextClick(link).perform();
            act.sendKeys("w").perform();

            Thread.sleep(4000);
//continue handling new window

Tag : java , By : Doc Immortal
Date : March 29 2020, 07:55 AM
wish of those help When you navigate to another page (or even refresh the current page) the previously located elements become stale, so you get StaleElementReferenceException. You need to relocate the links
driver.navigate().back();
links = driver.findElements(By.cssSelector("#amshopby-page-container > div.category-products > div.products > ul > li > div > h2 > a"));

How to get buttons of all forms on webpage using python selenium?


Tag : python , By : somebody
Date : March 29 2020, 07:55 AM
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