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How can i achieve the same functionality with Java 8 using streams


How can i achieve the same functionality with Java 8 using streams

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How can i achieve the same functionality with Java 8 using streams
Tag : java , By : Aki Björklund
Date : December 01 2020, 04:52 PM

To fix the issue you can do What I wanted to do was to add 10min if consecutive orders have the same postcode, otherwise, add 30 min to the journey. For example, if I have a class like the following this is how i achieve that imperatively. , You could use IntStream for that :
int totalMin =
IntStream.range(0, orders.size()-1)
         .map(i-> orders.get(i+1).getPostCode().equals(orders.get(i).getPostCode()) ? 10 : 30)
         .sum();

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Is it possible to use Java annotations, to achieve a similar functionality as a preprocessor


Tag : java , By : Johannes
Date : March 29 2020, 07:55 AM
To fix the issue you can do Annotations are not meant as a tool to transform code; they just add metadata to code. You can't use annotations for conditional compilation, for example.
As Sun's tutorial on annotations says:

Why can't I Implement Streams functionality in my JAVA project?


Tag : java , By : B3CFT
Date : March 29 2020, 07:55 AM
may help you . Streams and lambda expressions are Java 8 functionality. Upgrade your compiler.

if-elseif-else like functionality with Java 8 streams


Tag : java , By : Daljit Dhadwal
Date : March 29 2020, 07:55 AM
I hope this helps . I have a list of objects, lets say Shapes. I would like to process them using a stream and return another object - ShapeType - based on what is in the list. , You can use
public ShapeType resolveShapeType(final List<Shape> shapes) {
    int sides = shapes.stream()
        .mapToInt(Shape::getSideCount)
        .filter(count -> count==4 || count==6)
        .max().orElse(0);
    return sides==6? ShapeType.HEXA: sides==4? ShapeType.RECT: ShapeType.GENERIC;
}
public ShapeType resolveShapeType(final List<Shape> shapes) {
    OptionalInt first = IntStream.range(0, shapes.size())
        .filter(index -> {
            int count = shapes.get(index).getSideCount();
            return count == 6 || count == 4;
        })
        .findFirst();
    if(!first.isPresent()) return ShapeType.GENERIC;
    int ix = first.getAsInt(), count = shapes.get(ix).getSideCount();
    return count==6? ShapeType.HEXA: shapes.subList(ix+1, shapes.size()).stream()
        .anyMatch(shape -> shape.getSideCount()==6)? ShapeType.HEXA: ShapeType.RECT;
}

achieve replaceAll functionality in java 1.2


Tag : java , By : user93312
Date : March 29 2020, 07:55 AM

Using Java 8 Supplier in streams to achieve lazy evaluation


Tag : java , By : user181945
Date : March 29 2020, 07:55 AM
hope this fix your issue I don't think this is possible using only standard Java classes. But you could write your own lazy evaluator and use that, for example (untested):
public class LazyValue<T> implements Supplier<T> {
    private T value;
    private final Supplier<T> initializer;
    public LazyValue(Supplier<T> initializer) {
        this.initializer = initializer;
    } 
    public T get() {
        if (value == null) {
            value = initializer.get();
        }
        return value;
    }
}
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