How to read local xml file is resource folder as a input stream in android?
Date : March 29 2020, 07:55 AM
seems to work fine Put the xml file into /res/raw folder. It looks like openRawResource opens resources from that folder only. You can also try getResources().getXml(com.MYCLass.R.xml.programs); which will return you an instance of XML parser. A piece of code taken from @Krupa InputStream object = this.getResources()
.openRawResource(R.raw.fileName);
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Given an x264 stream and an ogg vorbis stream, how do I make a muxed stream that mplayer/VLC can read?
Tag : cpp , By : user109285
Date : March 29 2020, 07:55 AM
this one helps. x264 is not a stream format. It is a piece of software. This software encodes video to the H.264 video format. AFAIK, it does not mux video+audio into MP4 or AVI container files. Look into ffmpeg/libav for a full suite. There are other programs to mux video and audio streams. Here's an experiment I performed: youtube-dl "http://www.youtube.com/watch?v=0Bmhjf0rKe8"
avconv -i 0Bmhjf0rKe8.flv -vn -c:a libvorbis -b:a 64k 0Bmhjf0rKe8.ogg
avconv -i 0Bmhjf0rKe8.flv -c:v copy -bsf:v h264_mp4toannexb -an 0Bmhjf0rKe8.h264
avconv -i 0Bmhjf0rKe8.h264 -i 0Bmhjf0rKe8.ogg -c copy 0Bmhjf0rKe8.mkv
mplayer 0Bmhjf0rKe8.mkv
avconv -i 0Bmhjf0rKe8.flv -i 0Bmhjf0rKe8.ogg -c copy -map 0:0 -map 1:0 0Bmhjf0rKe8.mp4
mplayer 0Bmhjf0rKe8.mp4
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Elixir: can I use Stream.resource to progressively read a large data file?
Tag : elixir , By : Tim Benninghoff
Date : March 29 2020, 07:55 AM
should help you out As a side note, it is a common task to create a stream from a file. This has been taken care of, so you can simply use File.stream!/3 to create the stream, no need to use Stream.resource/3 directly. Regarding your original question: yes you are correct, Stream.chunk_every/2 is the way to go here. It will lazily split the stream into chunks of the supplied size: File.stream!("./data/fidap011.mtx") |> Stream.chunk_every(5) |> Enum.each(fn chunk ->
# do something with chunk
end)
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how to read Stream[String] after running scala process
Tag : scala , By : Justin Bowers
Date : March 29 2020, 07:55 AM
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Prevent Spring from attempting to read old resource stream
Tag : java , By : hammer_1968
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , Turns out there is a configuration for this, in an unexpected place. In my WebMvcConfigurerAdapter-extending config class, in the addResourceHandlers method: registry.addResourceHandler("**/pluginresource/**")
.setCacheControl(CacheControl.noStore() )
.resourceChain(false)
.addResolver(pluginResourceResolver);
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