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While loop stop condition missing


While loop stop condition missing

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While loop stop condition missing
Tag : java , By : yew tree
Date : December 01 2020, 04:45 PM

To fix the issue you can do The parent of 0 is also 0, you could argue that it's not really its own parent, but that's how the formula works out.
The root of the heap cannot be less than itself, so the loop stops there automatically.

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c while loop stop before condition


Tag : c , By : kakashi_
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further I have one exercise that I have to calculate fibonacci numbers until 100 and then print them. , I think that you can use a do ... while(cond). It should looks like :
#include <stdio.h>
#include <stdlib.h>

int main()
{

    int i=2,fibonacci = 0, fParcialone = 1, fParcialtwo = 0;
    printf("The %2dst Fibonacci number is %3d\n", i-1, fibonacci+1);
    fibonacci = fParcialone+fParcialtwo;
    do {
        printf("The %2dst Fibonacci number is %3d\n", i, fibonacci);
        fParcialtwo = fParcialone;
        fParcialone = fibonacci;
        i++;
    } while ((fibonacci = fParcialone+fParcialtwo) <= 100);
    return 0;
}

How to stop execution of a while loop's condition, if the condition fails


Tag : chash , By : Justin Bowers
Date : March 29 2020, 07:55 AM
Does that help you just simply use && instead of ||. Since the right condition is supposed to be checked only if the first one has returned true.

Loop inside loop. Stop second loop if condition is met


Tag : vba , By : user177910
Date : March 29 2020, 07:55 AM
To fix the issue you can do From your question, I assume there will be only one result in Sheets("DWAC") column C. With that in mind, we can use find instead of looping until you get a match.
If we cleaned up your Dim statements(there is one sheet not being used in the code & Row variables should be long.
    Dim D As Worksheet, R As Worksheet
    Dim ENDROW As Long, REND As Long
    Dim rng1 As Range, rng2 As Range
    Dim c As Range, FndC As Range
Set D = Sheets("DWAC")
Set R = Sheets("RAW")
 With D
    ENDROW = .Cells(.Rows.Count, "C").End(xlUp).Row
    Set rng2 = .Range("C2:C" & ENDROW) 'find value in column C sheet D
End With
With R
        REND = .Cells(.Rows.Count, "D").End(xlUp).Row
        Set rng1 = .Range("D2:D" & REND) 'Loop through column D in sheet R
    End With
 For Each c In rng1.Cells
        Set FndC = rng2.Find(what:=c, lookat:=xlWhole)
   If Not FndC Is Nothing Then

            If c.Offset(, 4) = FndC.Offset(, 3) Then
                c.Offset(, -3) = "Match"
            Else
                c.Offset(, -3) = "DIFFERENCE OF " & c.Offset(, 3) - FndC.Offset(, 3)
            End If
        Else: c.Offset(, -3) = "Not Found"

        End If
    Next c
c.Offset(, 4)'=Column H Sheet "R"
FndC.Offset(, 3)'=Column F Sheet "D"
c.Offset(, -3)'=Column A Sheet "R"
c.Offset(, 3)'=Column G Sheet "R"
Sub FindAndStuff()
    Dim D As Worksheet, R As Worksheet
    Dim ENDROW As Long, REND As Long
    Dim rng1 As Range, rng2 As Range
    Dim c As Range, FndC As Range

    Set D = Sheets("DWAC")
    Set R = Sheets("RAW")

    With D
        ENDROW = .Cells(.Rows.Count, "C").End(xlUp).Row
        Set rng2 = .Range("C2:C" & ENDROW) 'find value in column C sheet D
    End With


    With R
        REND = .Cells(.Rows.Count, "D").End(xlUp).Row
        Set rng1 = .Range("D2:D" & REND) 'Loop through column D in sheet R
    End With

    For Each c In rng1.Cells
        Set FndC = rng2.Find(what:=c, lookat:=xlWhole)

        If Not FndC Is Nothing Then

            If c.Offset(, 4) = FndC.Offset(, 3) Then
                c.Offset(, -3) = "Match"
            Else
                c.Offset(, -3) = "DIFFERENCE OF " & c.Offset(, 3) - FndC.Offset(, 3)
            End If
        Else: c.Offset(, -3) = "Not Found"

        End If
    Next c

End Sub

iterating an array backwards in For loop condition to stop at 0 when using unsigned integers causing infinite loop


Tag : c , By : mgaspar
Date : March 29 2020, 07:55 AM
should help you out size_t is an unsigned integer and it's never going to be less than 0. So the condition in for loop is always true:
for(j=i;j>=0;j--)
for(j=i; j-- > 0;){
   ...
}

While loop does not stop when the condition is met


Tag : python , By : Nick
Date : March 29 2020, 07:55 AM
Does that help It does not have printed the "greeting" yet, when it hits the break and stops the loop. Just move the print(greeting) to just before the if greeting == ....
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