How can I move a new record form into a related records show page?
Date : March 29 2020, 07:55 AM
This might help you Just add @review = Review.new to the show action on your venues controller. Then put the form right in your venue#show view file. venues_controller.rb def show
@venue = Venue.find(params[:id])
@review = Review.new
end
|
How can I list all records which belong to another record at the show page?
Date : March 29 2020, 07:55 AM
I wish this helpful for you First, can you show us your areas_controller.rb file please? Inside your view you can do this by doing: <% @area.venues.each do |venue| %>
<%= venue.name %>
# etc.
<% end %>
def show
@area = Area.find(params[:id])
end
class Area < ActiveRecord::Base
has_many :venues
end
class Venue < ActiveRecord::Base
belongs_to :area
end
|
Rails how to show on one page existing associated records AND permit new associated record input
Date : March 29 2020, 07:55 AM
may help you . ok, so @plate.translations is the set of current translations that are already on the plate. If you want a fields-for section for a new one... you have to actually build a new one. <%= f.fields_for :translations, [@plate.translations.build] do |fff| %>
<div>
<%= fff.text_field :meaning %>
</div><br><br>
<% end %>
|
How can I get my program back on track when printing out all student records?
Date : March 29 2020, 07:55 AM
wish of those help When you initialize the BinaryTreeArray(), you set the field variable "size" to 100 and use this to initialize the data Listing[] array. When you print out the data, the loop uses the same "size" variable so you get all 100 entries, including the null entries. A simple solution would be to filter the data for null when you show all. public class BinaryTreeArray
{
...
public void showAll()
{
for(int i=0; i<size; i++)
{
if (data[i] != null)
System.out.print(data[i] + " ");
}
}
...
}
|
load more records script show the same last record from a previous set of records if a new record is added
Date : March 29 2020, 07:55 AM
This might help you I'm very confused and I don't know how to solve this problem i'm not sure if I have to adjust the jQuery or the SQL to properly show this without duplicates. I just don't know, so I have this script that loads a set of records every time you press the load more button. , Your SQL query is correct but wrong for this situation. SELECT*FROM records WHERE NOT status='remove' ORDER BY ID DESC LIMIT $start, $limit";
|