Cann't delete row in php using AJAX

Cann't delete row in php using AJAX

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Cann't delete row in php using AJAX
Tag : php , By : Bado
Date : November 29 2020, 12:01 PM

may help you . The first problem is that, you're getting name attribute from your delete button. You can pass bni_member_id as a data attribute instead of using element id attribute. It can cause confusion. And the second problem is that, you're using both onlick attribute and jQuery's click method. Using one them is pretty enough. Your input button will look like this:
<td><input type="button" name="delete" value="delete" class="btn btn-info btn-xs delete_data" data-bni-member-id="<?= $row["bni_member_id"]; ?>" /></td>
$(document).ready(function () {
    $('.delete_data').click(function () {
        var del_id = $(this).data("bni_member_id");
        var $ele = $(this).parent().parent();
            url: "phpfile/delete.php",
            method: "POST",
            data: {del_id: del_id},
            success: function (data) {
                } else {
                    alert("can't delete the row")

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cannt get a record by the row number

Tag : sql , By : Pepe Araya
Date : March 29 2020, 07:55 AM
I wish this help you i get an error with this query
(select ID, ROW_NUMBER() OVER(ORDER BY ID) as rownum from T_TASK) dr
WHERE rownum = 5

the code cannt be run because of this error?

Tag : python , By : mux
Date : March 29 2020, 07:55 AM
will help you Yes, Because you have a break that doesn't have anything to break from.
Just remove it.
process_queue = []
total_wtime = 0
n = int(raw_input('Enter the total no of processes or 0 to quit: '))

if n == 0:
    print 'good bye!'
if n == 0:
    print 'good bye!'
elif n == 1:
    print 'Hello!'
    print 'Input not recognized'

Cannt get value of Global variable temp

Tag : javascript , By : Jojo
Date : March 29 2020, 07:55 AM
it fixes the issue You seem to be redefining your temp var inside each function instead of using the global temp var you define at the top. When you assign " " to temp inside your function, the variable scope to the function and not the global one.
try temp = " "

cannt import v7 library

Tag : android , By : Nick Coats
Date : March 29 2020, 07:55 AM
wish helps you I want to know why my Android studio Cannot resolve AppCompactActivity symbol, when I try to add the AppCompat v7 library This import statement , Add AppCompat Library in Gradel file.
compile "com.android.support:support-v4:${androidSupportLibraryVersion}"
compile "com.android.support:appcompat-v7:${androidSupportLibraryVersion}"
compile "com.android.support:support-annotations:${androidSupportLibraryVersion}"
File->Invalidate Caches/Restart

cannt using int value Inside a string code?

Tag : php , By : Bin
Date : March 29 2020, 07:55 AM
help you fix your problem I want to do is find a value and try to pass it inside the text function and the more i put the variable $index error occurs although everything is intact, i use php 7, but I don't know why. , 1. Your concatenation is incorrect:
$sql = "SELECT * FROM users WHERE id = . ($index) .";
$sql = "SELECT * FROM users WHERE id =" . $index;
$sql = "SELECT * FROM users WHERE id ={$index}";
$filter_id = [];
foreach($filters as $obj){
   $filter_id[] = $obj->tokens;
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