  C RUBY-ON-RAILS MYSQL ASP.NET DEVELOPMENT RUBY .NET LINUX SQL-SERVER REGEX WINDOWS ALGORITHM ECLIPSE VISUAL-STUDIO STRING SVN PERFORMANCE APACHE-FLEX UNIT-TESTING SECURITY LINQ UNIX MATH EMAIL OOP LANGUAGE-AGNOSTIC VB6 MSBUILD # Needing formula for a compounding number multiplied by a value (Not anually)

## Needing formula for a compounding number multiplied by a value (Not anually) Tag : google-sheets , By : user181706 Date : November 29 2020, 12:01 PM

it should still fix some issue Looking for very simple compounding math. , Most likely you seek something simple as:
``````=A22*2^3
``````
``````=A22*2*2*2
``````
``````=(A22*B22)*2^3
`````` Boards Message : You Must Login Or Sign Up to Add Your Comments .

## Summing and rounding fractions multiplied by number to equal number?

Tag : javascript , By : Lucas Thompson
Date : March 29 2020, 07:55 AM
like below fixes the issue Use the Largest Remainder Method:
Step 1: Multiply the numbers by n (in this case, let's use an n that doesn't immediately work out so nicely to demonstrate that the LRM still works; I choose 737), and separate the whole and fractional parts.
``````0.3 * 737 = 221 + 0.1
0.3 * 737 = 221 + 0.1
0.2 * 737 = 147 + 0.4
0.1 * 737 = 73 + 0.7
0.1 * 737 = 73 + 0.7
``````
``````221 + 221 + 147 + 73 + 73 = 735
``````
``````High to low: 0.7, 0.7, 0.4, 0.1, 0.1
``````
``````221
221
147
74
74
``````

## How do I make is so the entered number is multiplied by the slider number

Tag : xcode , By : helloedwin
Date : March 29 2020, 07:55 AM
will be helpful for those in need Thats because your slider.value returns a Float. You are trying to convert the result of it but you need to convert just the slider.value to Int to multiply it by numbers which is an Int. Try like this:
Note: As mentioned by Josh you need also to unwrap toInt() optional result. You can use "??" nil coalescing operator to return 0 in case of invalid input.
`````` let numbers = multiplier.text.toInt() ?? 0

let timesTable = Int(sliderValue.value) * numbers
``````

## Count number of non-prime pairs that when multiplied form a given number N,

Tag : java , By : unadopted
Date : March 29 2020, 07:55 AM
Hope that helps First of all, Eratosthenes' sieve is O(N*log(log(N)) to list all primes below or equal N (when well implemented).
Second: suppose you factored your number in Q primes with multiplicity which, without sieving, is a process of O(sqrt(N)) at worst (worst: your number is prime). So you have a map of:
``````import java.util.HashMap;
import java.util.Map;

class Example {

static void factor(long N, Map<Long, Short> primesWithMultiplicity) {
// some arg checking and trivial cases
if(N<0) N=-N;
if(0==N) {
throw new IllegalArgumentException(
"Are you kidding me? Every number divides 0, "+
"you really want them all listed?"
);
}
if(1==N) {
primesWithMultiplicity.put(1L,(short)1);
return;
}

// don't try divisors higher than sqrt(N),
// if they would have been detected by their composite-complement
for(long div=2; div*div < N; ) {
short multiplicity=0;
while((N % div)==0) {
multiplicity++;
N /= div; // reduce N
}
if(multiplicity>0) {
primesWithMultiplicity.put(div, multiplicity);
}
div+= (div == 2 ? 1 : 2); // from 2 to 3, but then going only on odd numbers
}
// done.. well almost, if N is prime, then
// trying to divide up to sqrt(N) will lead an empty result. But,
// in this case, N will still be at original value (as opposed
// to being 1 if complete factored)
if(N>1) {
primesWithMultiplicity.put(N, (short)1);
}
}

static int countDistinctCompositePairs(long N) {
HashMap<Long, Short> factoringResults=new HashMap<>();
factor(N, factoringResults);
int ret=1;
for(short multiplicity : factoringResults.values()) {
ret*=multiplicity;
}
return ret/2;
}

static public void main(String[] args) {
System.out.println(countDistinctCompositePairs(24));
}
}
``````

## Excel VBA loop using relative references and needing a fixed cell in the formula

Tag : excel-vba , By : Meg
Date : March 29 2020, 07:55 AM
hop of those help? I am coding two loops. The first loop sums a column 14 times and then goes through each worksheet in the workbook until they are all calculated. The second loop is more complex. The formula, if you were to enter it manually should be =(OFFSET(N39, -1, 0, 1, 1)) / (OFFSET(\$N\$39, -1, -1, 1, 1)). This formula should loop 13 times. Each time it calculates, it should give the percentage of a total bucket, so as an example, it could tell you that 93% of your accounts receivables are current, then 2% are 1-10 days late, then 1.5% is 11-30 days late, etc. I cannot figure out how to code the loop that is calculating the percentage of each column. Below is my code: , Try to alter the For Loop to the following:
``````x = 1
For g = 14 To 26
lastrow = ActiveSheet.Cells(Rows.Count, "N").End(xlUp).Row + 1
ActiveSheet.Cells(lastrow, g).Value = "=R[-1]C/R[-1]C[-" & x & "]"
x = x + 1
Next g
``````

## How to make a table of the frequency of a number multiplied by the number raised to 3 in R

Tag : r , By : MikeG
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , Having the following list, I would like the result of the frequency to be multiplied by its index value raised to 3. How could I do it?
``````with(rle(sort(data)), lengths*values^3)
#      2     16     54  39304 549250 474552
``````
``````x = table(data)
x*as.numeric(names(x))^3
#data
#1      2      3     34     65     78
#2     16     54  39304 549250 474552
`````` Related QUESTIONS : 