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creating multiple rows based on record in an array - laravel


creating multiple rows based on record in an array - laravel

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creating multiple rows based on record in an array - laravel
Tag : php , By : k19k
Date : November 28 2020, 12:01 PM

wish of those help I have the following query that brings back an array of user_ids, where each user will get notified. , Use for loop for this:
foreach($pstusrmembs as $userID){
        $notifs = new Notif();
        $notifs->rec_uid = $userID;
        $notifs->title = $post_title;
        $notifs->save();
}
foreach ($pstusrmembs as $userID) {
    Notif::create(['rec_uid' => $userID, 'title' => $post_title]);
  }
foreach ($pstusrmembs as $userID) {
     $arrayOfNotif[] = ['rec_uid' => $userID, 'title' => $post_title];
  }

  Notif::insert($arrayOfNotif);

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Return multiple rows based on int value from a single record


Tag : mysql , By : Chris Hanley
Date : March 29 2020, 07:55 AM
Does that help You can do something like this, joining a dummy range of numbers against itself to get the range of numbers, then adding that to the base month
SELECT id, name, DATE_FORMAT(DATE_ADD(start_date, INTERVAL Units.i + Tens.i * 10 + Hundreds.i * 100 MONTH), '%Y-%m') AS `month`, (amount / duration) AS `amount_this_month`
FROM SomeTable
CROSS JOIN (SELECT 0 AS i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) Units
CROSS JOIN (SELECT 0 AS i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) Tens
CROSS JOIN (SELECT 0 AS i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) Hundreds
WHERE (Units.i + Tens.i * 10 + Hundreds.i * 100) < duration

Select one record based on results from multiple rows


Tag : mysql , By : Ike
Date : March 29 2020, 07:55 AM
hope this fix your issue I have two tables: , try this
   SELECT
    c.id
   FROM conversations c
   JOIN conversation_participants p ON p.conversation_id = c.id
   JOIN conversation_participants p2 ON p2.conversation_id = p.conversation_id
   WHERE  c.project_id = ?
   AND p.user_id = ? and p2.user_id = ?
p.user_id = 1   --as user1
p2.user_id = 2  --as user2
c.project_id = 1 

Laravel Eloquent ORM method for Retrieving Multiple Rows based on an Array of ids


Tag : php , By : Bharath
Date : March 29 2020, 07:55 AM
it helps some times I might not have phrased the question the way I wanted to but here's my Dilema: , This seems to do the trick:
/*groups the expiring policies for each user*/
$with_expiring = $expiring->groupBy('client_id');

/*counts the number of clients with expiring policies instead of
 *counting the number of expiring policies first then checking
 *against a list of 'client_id's
 */
$total_with_expiring = $with_expiring->count();

/*groups the expired policies for each user*/
$with_expired = $expired->groupBy('client_id');

/*counts the number of clients with expired policies instead of
 *counting the number of expired policies first then checking
 *against a list of 'client_id's
 */
$total_with_expired = $with_expired->count();

SQL: Create multiple rows for a record based on months between two dates


Tag : sql , By : paolodm
Date : March 29 2020, 07:55 AM
this one helps. My table has records as below for different Id's and different start and end dates , This is what I did and it worked like a charm:
-- sample data  
WITH table_data
AS (
    SELECT 1 AS id
        ,cast('2017-08-14' AS DATE) AS start_dt
        ,cast('2018-12-16' AS DATE) AS end_dt

UNION ALL

SELECT 2 AS id
    ,cast('2017-09-14' AS DATE) AS start_dt
    ,cast('2019-01-16' AS DATE) AS end_dt
)

-- find minimum date from the data  
,starting_date (start_date)
AS (
SELECT min(start_dt)
FROM TABLE_DATA
)

--get all months between min and max dates  
,all_dates
AS (
SELECT last_day(add_months(date_trunc('month', start_date), idx * 1)) month_date
FROM starting_date
CROSS JOIN _v_vector_idx
WHERE month_date <= add_months(start_date, abs(months_between((
                    SELECT min(start_dt) FROM TABLE_DATA), (SELECT max(end_dt) FROM TABLE_DATA))) + 1)
ORDER BY month_date
)
SELECT id  
,extract(year FROM month_date)  
,extract(month FROM month_date)  
,td.start_dt  
,td.end_dt  
FROM table_data td  
INNER JOIN all_dates ad  
    ON ad.month_date > td.start_dt  
        AND ad.month_date <= last_day(td.end_dt)  
ORDER BY 1  
    ,2  

Creating a new column in dataframe based on multiple conditions from other rows and columns? Including rows that are nul


Tag : python , By : Lucas Thompson
Date : March 29 2020, 07:55 AM
like below fixes the issue The reason the code you shared for assigning multiple values doesn't work is because df['SPOTTED'] = assigns to the entire column. Therefore the code keeps creating and overwriting the same column.
Next time you encounter an issue of the sorts, try looking at the contents of df after each operation.
import numpy as np
import pandas as pd

df = pd.DataFrame({'work_date': [1, 2, 3, 4, np.nan], 'time_code': ['WRK', 'OFF', 'VAT', 'BONUS', 'OT15']})

select_time_codes = ['VAT', 'WRK', 'OFF']

df.loc[df['work_date'].notna() & df['time_code'].isin(select_time_codes), 'spotted'] = 'No'
   work_date time_code spotted
0        1.0       WRK      No
1        2.0       OFF      No
2        3.0       VAT      No
3        4.0     BONUS     NaN
4        NaN      OT15     NaN
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