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Identifying sender from Control.InvokeOnClick()


Identifying sender from Control.InvokeOnClick()

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Identifying sender from Control.InvokeOnClick()
Tag : chash , By : user118656
Date : November 27 2020, 12:01 PM

This might help you Reference Source reveals the answer. InvokeOnClick calls protected method OnClick of target control, which then invokes Click event with this (equal to target control) as sender meaning that the target control will be the sender parameter for its own Click event.
// snippet from Reference Source

protected void InvokeOnClick(Control toInvoke, EventArgs e) {
    if (toInvoke != null) {
        toInvoke.OnClick(e);
    }
}

// ...

protected virtual void OnClick(EventArgs e) {
    Contract.Requires(e != null);
    EventHandler handler = (EventHandler)Events[EventClick];
    if (handler != null) handler(this, e);
}

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Object sender to control sender?


Tag : chash , By : brennen
Date : March 29 2020, 07:55 AM
Hope that helps Assuming you are talking about the object sender argument of an event handler, then you can always cast it to a control.
if(sender is Control)
{
   var myControl = sender as Control;
}

Get access to the Sender control - C#


Tag : chash , By : Giles
Date : March 29 2020, 07:55 AM
wish help you to fix your issue In your click handler, cast the 'sender' parameter to a PictureBox and examine its Location.
void pb_point_Click(object sender, EventArgs e)
{
    var pictureBox = (PictureBox)sender;
    MessageBox.Show(pictureBox.Location.ToString());
}

What conditions prevent PerformClick from working but allow InvokeOnClick to work?


Tag : chash , By : Tim
Date : March 29 2020, 07:55 AM
Any of those help As far as I know:
The button and all of its parents must be enabled and visible The control must be selectable (ControlStyles.Selectable) The validation rules must be fulfilled

Where is InvokeOnClick() method called when I click a button in C# WinForms?


Tag : chash , By : Nathan Good
Date : March 29 2020, 07:55 AM
wish help you to fix your issue InvokeOnClick is currently not used.
The Click event is raised by the Control.OnClick method:
EventHandler handler = (EventHandler)Events[EventClick];
if (handler != null) handler(this, e);

invokeOnClick error in c++


Tag : .net , By : Janko
Date : March 29 2020, 07:55 AM
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