Finding absolute value of a number without using Math.abs()
Date : March 29 2020, 07:55 AM
wish of those help If you look inside Math.abs you can probably find the best answer: Eg, for floats: /*
* Returns the absolute value of a {@code float} value.
* If the argument is not negative, the argument is returned.
* If the argument is negative, the negation of the argument is returned.
* Special cases:
* <ul><li>If the argument is positive zero or negative zero, the
* result is positive zero.
* <li>If the argument is infinite, the result is positive infinity.
* <li>If the argument is NaN, the result is NaN.</ul>
* In other words, the result is the same as the value of the expression:
* <p>{@code Float.intBitsToFloat(0x7fffffff & Float.floatToIntBits(a))}
*
* @param a the argument whose absolute value is to be determined
* @return the absolute value of the argument.
*/
public static float abs(float a) {
return (a <= 0.0F) ? 0.0F - a : a;
}
|
Math.Abs() does not create an exact, absolute Value
Date : March 29 2020, 07:55 AM
wish helps you This type of detection, to detect when one value is negative and the other positive (order is irrelevant), you should use the Math.Sign method: if (Math.Sign(a) != Math.Sign(b)) { ... }
|
How do I get the absolute value of an integer without using Math.abs?
Date : March 29 2020, 07:55 AM
|
How to find the difference of two numbers and the absolute value of that answer without using math.abs function JAVA
Tag : java , By : user179190
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further How can I find the absolute value of the difference of two numbers. (BEGINNER) , A bit more formatted code. import java.util.Scanner;
class A {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
double a;
double b;
System.out.println("Enter a: ");
a = in.nextDouble();
System.out.println("Enter b: ");
b = in.nextDouble();
double value = a - b;
//If value is negative...make it a positive number.
value = (value < 0) ? -value : value;
System.out.println("|"+a + "-" + b +"|" + " =" + value); // value should be printed here instead of (a-b) or (b-a)
System.out.println("|"+b + "-" + a +"|" + " =" + value);
}
}
|
How to get absolute value for a double value within a function (Without using math.h)
Tag : c , By : Marianisho
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further You can do the comparison and put the result (In case of negative double value prepend it with unary - (unary minus) else the value is positive). Using a simple if statement will be best way to deal with this. if( dblVal < 0 )
dblVal = -dblval;
double myabs(double d){
if( d < 0 )
return -d;
return d;
}
|