How to get data from a string

I wish this help you Seems to me you could pass ID & Column1 values from Table1 to a Table-Valued function (or a temp table in-line) which would parse the ;-delimited list, returning individual values per record.
Here are a couple options:

SELECT tmp.ID
FROM tmp
LEFT JOIN Table2 ON Table2.id = tmp.ID
WHERE Table2.id is null

I hope this helps . It's a new string.
Strings, in .NET, are always immutable. Whenever you generate a new string via a method, including Substring, it will construct the new string in memory. The only time you share references to the same data in strings in .NET is if you explicitly assign a string variable to another string (in which its copying the reference), or if you work with string constants, which are typically interned. If you know your string is going to share a value with an interned string (constant/literal from your code), you can retrieve the "shared" copy via String.Intern.

it fixes the issue i want to retrieve all data that are present in my data structure, which is of type Map of Maps.The data structure is mentioned below. , This may help you

Map<String,Map<String,String>> hourlyMap = new HashMap<String,Map<String,String>>();
    for(Map<String,String> i:hourlyMap.values()){
        // now i is a Map<String,String>
        for(String str:i.values()){
            // now str is a value of map i
            System.out.println(str);
        }
    }

I hope this helps . The workaround to this issue is to use the PostgreSQL UNICODE driver instead of the RedShift one. It seems there might be a bug in the RedShift driver which causes this behavior. I've informed AWS support and they are looking into it.

To fix this issue I am trying to generate a particularly structured dataframe, but i cant seem to "stack" the data. My sample raw data: , After pd.melt , do the following:

df['aggval'] = df['Week'].map(str) + df['Rotation']
df['aggval'] = df.groupby(['aggval']).cumcount()+1
pivot = df.pivot_table(index=['Rotation','aggval'], columns='Week', values='Name', aggfunc=lambda x: ' '.join(x)).fillna('')
pivot = pivot.reindex(weeks, axis=1)