Regluar expression problem. It does not find the needed part of the string

Regluar expression problem. It does not find the needed part of the string

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Regluar expression problem. It does not find the needed part of the string
Tag : chash , By : uxn
Date : November 24 2020, 12:01 PM

To fix the issue you can do I have to parse a build log file and find some header file which went missing when I exported my working sandbox. In C++ I managed to solve this issue, but the same pattern didn't work for C#. , You may use
string errLns = System.IO.File.ReadAllText(logFilePath);
List<string> hdrFiles = new List<string>();
string rgxPat = @"\bcan't\s+find\s+include\s+file\s+(?:\w+\/)*(\w+\.(?:hed?|hdb|h))\b";
Regex incLRgx = new Regex(rgxPat, RegexOptions.IgnoreCase);
hdrFiles.AddRange(incLRgx.Matches(errLns).Cast<Match>().Select(x => x.Groups[1].Value).ToArray());

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Regular expression to find exact part in a string using php

Tag : php , By : pcoramc
Date : March 29 2020, 07:55 AM
may help you . What should I use as a regex in order to get just the text between the double qoutes after url= , You regexp would be
$string = "your string here";

echo urldecode(base64_decode(preg_replace('/^.*url="(.*)".*$/', '$1', $string)));

Find what part of a string do not match with regular expression python

Tag : python , By : usingtechnology
Date : March 29 2020, 07:55 AM
seems to work fine Maybe this is a longer solution but it will tell you what failed and what it expected. It is similar to Kasra's solution - breaking up the file name into individual bits and matching them in turn. This allows you to find out where the matching breaks:
import re
# break up the big file name pattern into individual bits that we can match
RX      = re.compile
pattern = [

# 'fn' is the file name matched so far
def reductor(fn, rx):
    if fn is None:
        return None
    mo = rx.match(fn)
    if mo is None:
        print "File name mismatch: got {}, expected {}".format(fn, rx.pattern)
        return None
    # proceed with the remainder of the string
    return fn[mo.end():]

validFile = lambda fn: reduce(reductor, pattern, fn) is not None
print validFile("*S_hc_1.2.3_2014-213T123121.xml*")
print validFile("*S_hc_1.2.IncorrectName_2014-213T123121.xml*")
File name mismatch: got IncorrectName_2014-213T123121.xml*, expected [0-9]{1,2}

Php find a part of string using regular expression

Tag : php , By : dantino
Date : March 29 2020, 07:55 AM
will be helpful for those in need Why regex for this kind of simple task? use strpos with the combination of substr or just used explode() with @ as first parameter as directed by other answers.
$email_string = "mirko@gmail.com";    
$result = substr($email_string, strpos($email_string, "@") + 1);    
echo $result ;

VSCode Find and Replace - find instances where part of search expression matches criteria and part does not

Tag : javascript , By : Kaveh
Date : March 29 2020, 07:55 AM
I hope this helps you . I want to run a regex to find instances in my code where I declare an animation duration time: e.g. duration: 2000 and replace them with that duration plus an added variable timeScale, e.g. duration: timeScale * 2000 , As per your feedback, make sure you set useRipGrep to false and use

How can i find specific part of string in python regular expression?

Tag : python , By : rhinojosa
Date : March 29 2020, 07:55 AM
help you fix your problem The issue is that you are not using "or" (|), but instead a colon; Try using:
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