Expression with Math.random() always returns the same value

Expression with Math.random() always returns the same value

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Expression with Math.random() always returns the same value
Tag : java , By : user183954
Date : December 05 2020, 12:18 PM

Hope that helps The cast of Math.random() to int is occurring before the multiplication by 6. The cast operator is of higher precedence than *.
The Math.random() method returns a random number between 0 (inclusive) and 1 (exclusive), so the cast always returns 0.
int u = (int) (Math.random()*6) + 1;

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Math.random() returns value greater than one?

Tag : javascript , By : jumpingmattflash
Date : March 29 2020, 07:55 AM
hope this fix your issue The edge case occurs when you happen to generate a very small number, expressed with an exponent, like this for example 9.546056389808655e-8.
Combined with parseInt, which interprets the argument as a string, hell breaks loose. And as suggested before me, it can be solved using Math.floor.
var test = 9.546056389808655e-8;

console.log(test); // prints 9.546056389808655e-8
console.log(parseInt(test)); // prints 9 - oh noes!
console.log(Math.floor(test)) // prints 0 - this is better

(Math.random()*x)+y returns numbers greater than x+y

Tag : javascript , By : user183526
Date : March 29 2020, 07:55 AM
Hope that helps So I've been using HTML canvas and Javascript to create random images. Most of it is running pretty smoothly, but recently I've been encountering problems. , It happens because you're passing strings as arguments.
getRandomInt('0', '256') // 1540

Math.floor(Math.random() * val.length) returns a letter not a number

Tag : javascript , By : kgw
Date : March 29 2020, 07:55 AM
hope this fix your issue What you're doing right now with val[Math.floor(Math.random() * val.length)] is picking a random character from the string val (the value of the href attribute on the a element in question).
You probably want to make an array of all the images from the then use the original code to get a random one from that array
var imgArray = $(data).find("a").filter(function(){
  return this.href.match(/\.(jpe?g|png|gif)$/)
    return images + this.href

var randomNumber = Math.floor(Math.random() * imgArray.length);         

Why does math.random(999999999999) returns 1 in Lua?

Tag : math , By : user184415
Date : March 29 2020, 07:55 AM
like below fixes the issue This problem is surely because math.random treats the input arguments passed in Lua 5.1 and/or 5.2. From [mathlib.c]1:
As you may know in C, a standard int can represent values -2,147,483,648 to 2,147,483,647. Adding +1 to 2,147,483,647, like in your use-case, will overflow and wrap around the value giving -2,147,483,648. The end result is negative since you're multiplying a positive with a negative number.

How to explain that Observable.of(Math.random()) always returns the same value?

Tag : javascript , By : NewGirl
Date : March 29 2020, 07:55 AM
Hope this helps The value passed to of is prepared when the code is read. This is only a JS thing nothing related to RxJs in particular. Even if you don't subscribe to the observable. Ex:
const MyMathRandom = () => {
  console.log('MyMathRandom has been run');
  return Math.random();

const test = of(MyMathRandom())
const source = defer(() => of(Math.random()))

source.subscribe(x => console.log(x));
source.subscribe(x => console.log(x));
source.subscribe(x => console.log(x));
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