XmlSlurper to parse XML and get value of inside elements using Groovy

XmlSlurper to parse XML and get value of inside elements using Groovy

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XmlSlurper to parse XML and get value of inside elements using Groovy
Tag : java , By : mhedberg
Date : December 05 2020, 12:18 PM

To fix this issue I believe that this depthFirst().findAll { it.name() == 'section'} returns an array list which element is a combination of the inner text of p tags.
Let's define your sample XML as xmlDoc. Below is the snippet of code that works as expected:
def parseBodyObject = new XmlSlurper().parseText(xmlDoc)
def findAllPtags = parseBodyObject.children().depthFirst().findAll { 
   it.name() == 'p'
def docText = new StringBuilder()
findAllPtags.each { p ->
   docText.append("\n" + p)

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groovy XmlSlurper not parse my xml file

Tag : xml , By : user161314
Date : March 29 2020, 07:55 AM
Does that help You don't need to dereference the top tag (Entersgene-Set>). The following works for me in groovyconsole:
xml = """<Entrezgene-Set>
   <Entrezgene_summary>The protein encoded by this gene is a plasma glycoprotein of unknown function. The protein shows sequence similarity to the variable regions of some immunoglobulin supergene family member proteins. [provided by RefSeq]

def eFetchResult = new XmlSlurper().parseText(xml)
x = eFetchResult.Entrezgene.Entrezgene_summary
println "x is [${x}]"

groovy XmlSlurper parse XML

Tag : groovy , By : beng
Date : March 29 2020, 07:55 AM
Hope this helps Assuming you have the original xml in a variable called xml, you can do:
String output = new groovy.xml.StreamingMarkupBuilder().bind {
    mkp.yield new XmlSlurper().parseText( xml ).Body
<soap:Body xmlns:soap='http://www.w3.org/2003/05/soap-envelope'>
    <udb:ProvideUDBIdentityInformationRequest xmlns:udb='http://somenamespace'>

Parse XML using Groovy and XmlSlurper and iterate the tags

Tag : xml , By : Bimal Poudel
Date : March 29 2020, 07:55 AM
This might help you As a quick and relayable way to solve your problem I suggest you to create a factory method, that will give you initialised Worklog instance by issue key.
In that case, you will be able process xml same as you do, with minor changes. Below is a draft of code, to process worklogs.
def worklogs = [:]
def createWorklog(String id) {
   if (!worklogs.containsKey(id))
     worklogs[id] = new Worklog()
   return worklogs[id]

worklogs.worklog.each {node ->
    wklog = createWorklog(node.issue_key); // creates, or give created, and save it to list.

    // It don't know, what do you want to do with different dates or usernames.
    // If you want, you can have a list of them, and add value to list here, or consolidate whole change structures to list.
    wklog.hours += node.hours // aggregate hours.

Groovy XMLSlurper Parse Values

Tag : groovy , By : user112141
Date : March 29 2020, 07:55 AM
To fix this issue You need not require to use XmlUtil.serialize()
Here is what you need and following inline comments.
//Define which server you need
def SERVER = 'testserver1'
//Pass the 
def serverList = new 

//Get the filtered file names
def output = serverList.Server.findAll{it.@name == SERVER}.'**'.findAll{it.name() == 'File'}*.text()

println output
return output

Is it possible to parse sub-trees with Groovy XMLSlurper

Tag : groovy , By : dormsbee
Date : March 29 2020, 07:55 AM
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