Is there a way to automatically resolve an overloaded method via a template parameter?

Is there a way to automatically resolve an overloaded method via a template parameter?

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Is there a way to automatically resolve an overloaded method via a template parameter?
Tag : cpp , By : Blaise Roth
Date : December 05 2020, 12:18 PM

it helps some times You have to be explicit about which overload you want to use.
You can replace the static_cast with template parameters:
template <typename R, typename... ARGS>
R locked_call (R (List::*op)(ARGS...), ARGS... args) const {
    std::lock_guard<Mutex> g(lock_);
    return (list_.*op)(args...);

void add (int p) {
    locked_call<void, const int &>(&List::push_back, p);
template <typename OP, typename... ARGS>
auto locked_call (OP op, ARGS... args) const -> decltype((list_.*op)(args...)) {
    std::lock_guard<Mutex> g(lock_);
    return (list_.*op)(args...);

void add (int p) {
    void (List::*m)(const int &) = &List::push_back;
    locked_call(m, p);

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Unable to resolve overloaded class methods in template delegate

Tag : cpp , By : nseibert
Date : March 29 2020, 07:55 AM
hop of those help? Background: I'm using a delegation technique to abstract access to arbitrary object methods, but I'm having some issues where the linker is concerned. Consider the following class, ContextNode. , You can use a cast to disambiguate an overloaded function name:
(int (Thing::*)(void))(&Thing::value)
(void (Thing::*)(const int&))(&Thing::value)

what happens when overloaded method has template class as parameter

Tag : cpp , By : ponchopilate
Date : March 29 2020, 07:55 AM
With these it helps A non-template function is a better match than a function template.
Reference (C++ Draft Standard N3337):

Doxygen complains about overloaded functions that take same template but with different template parameter

Tag : cpp , By : obijywk
Date : March 29 2020, 07:55 AM
will be helpful for those in need I found a rather ugly way to make it work until the bug gets fixed in Doxygen. It seems to work at least for my case. I suppose it affects some links, though, but at this point I think I prefer to get the expected description for each function than having proper links and namespace names.
I thought about the fact that Doxygen accepts preprocessor options which can be used to add a Doxygen specific #define. Here is my doxygen.h header:

#ifdef DOXYGEN
#define no_name             doxygen
#define no_name

namespace no_name
    // static code goes here
} // no name namespace
PREDEFINED             = DOXYGEN=1
EXPAND_AS_DEFINED      = no_name

C++ Template: cannot find base class type parameter method when overloaded

Tag : cpp , By : Ed.
Date : March 29 2020, 07:55 AM
this one helps. The reason is that method foo in class Derived hides all methods with the same name which are inherited from class Base. Consequently, only a single version of method foo which accepts std::string as parameter is available for a call through Derived. As a result you have to call foo which accepts no arguments explicitly using the syntax:
class Derived : public Base {
  using Base::foo;
  void foo(std::string str) { std::cout << str << std::endl; }

How do I resolve an overloaded function by it's signature as a template parameter?

Tag : cpp , By : Rohii
Date : March 29 2020, 07:55 AM
Any of those help You can add a * to the signature to get the right function pointer type.
template<typename Signature, Signature* fptr>
auto make_delegate()
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