WPF - Create solid layout without designer

WPF - Create solid layout without designer

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WPF - Create solid layout without designer
Tag : chash , By : Robert MacGregor
Date : November 29 2020, 04:01 AM

With these it helps The easiest way to place controls in WPF without overlapping them is to use and . You can either define your width and heights with fixed or relative values (using '*'). For good and simple explanation I can suggest these two sites:

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How to create a circle shape without solid polygon or non solid circle``

Tag : development , By : Adil
Date : March 29 2020, 07:55 AM
With these it helps You can do this using a single body for the roulette wheel. Use a circle shape for the "inner" part of it and a chain shape for the "outer" part of it.
You should probably use "spikes" in the chain shape to add something for the ball to bounce off of. Here is the main creation function:
void MainScene::CreateBody()
   const float32 INNER_RADIUS = 2.50;
   const float32 OUTER_RADIUS = 3.0;
   const float32 BALL_RADIUS = 0.1;
   const uint32 DIVISIONS = 36;

   Vec2 position(0,0);

   // Create the body.
   b2BodyDef bodyDef;
   bodyDef.position = position;
   bodyDef.type = b2_dynamicBody;
   _body = _world->CreateBody(&bodyDef);
   assert(_body != NULL);

   // Now attach fixtures to the body.
   FixtureDef fixtureDef;
   fixtureDef.density = 1.0;
   fixtureDef.friction = 1.0;
   fixtureDef.restitution = 0.9;
   fixtureDef.isSensor = false;

   // Inner circle.
   b2CircleShape circleShape;
   circleShape.m_radius = INNER_RADIUS;
   fixtureDef.shape = &circleShape;

   // Outer shape.
   b2ChainShape chainShape;
   vector<Vec2> vertices;
   const float32 SPIKE_DEGREE = 2*M_PI/180;
   for(int idx = 0; idx < DIVISIONS; idx++)
      float32 angle = ((M_PI*2)/DIVISIONS)*idx;
      float32 xPos, yPos;

      xPos = OUTER_RADIUS*cosf(angle-SPIKE_DEGREE);
      yPos = OUTER_RADIUS*sinf(angle-SPIKE_DEGREE);

      xPos = OUTER_RADIUS*cosf(angle)*.98;
      yPos = OUTER_RADIUS*sinf(angle)*.98;

      xPos = OUTER_RADIUS*cosf(angle+SPIKE_DEGREE);
      yPos = OUTER_RADIUS*sinf(angle+SPIKE_DEGREE);
   chainShape.CreateChain(&vertices[0], vertices.size());
   fixtureDef.shape = &chainShape;

   // Create some "spikes" for the ball to bounce off of.

   // Start it spinning

   // NOW create a ball to bounce around inside...
   bodyDef.position = Vec2((INNER_RADIUS+OUTER_RADIUS)/2,0);
   _ballBody = _world->CreateBody(&bodyDef);
   circleShape.m_radius = BALL_RADIUS;
   fixtureDef.shape = &circleShape;

   // Give it some velocity so it starts to bounce.

Qt designer: How to add widget to a layout in the designer when the layout appears infinitely thin?

Tag : qt , By : user170635
Date : March 29 2020, 07:55 AM
may help you . Select the layout, and then drop the widget onto the corresponding selected item in the Object Inspector pane. If you find it tricky to select the layout on the actual form, you can also select it via the Object Inspector pane.

Android: How do I put a solid color rectangle in a Layout?

Tag : android , By : Grik
Date : March 29 2020, 07:55 AM
this one helps. Classes are case sensitive - in this case, you are using the View class and therefore it needs to be exactly View in your XML.

Layout in Emulator Different With Layout in Designer

Tag : android , By : user176691
Date : March 29 2020, 07:55 AM
like below fixes the issue I code using Android Studio. I found some problem that layout in emulator and APK (Build APK and run in my gadget) is different with layout when I design in deisgner. What is wrong with my code ? Or is there something I must set ? , Each view in your layout has attributes like these:

The designer has given me the PSD. Now, how do I create my android layout?

Tag : android , By : Pat
Date : March 29 2020, 07:55 AM
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