Collation Problem in asp.net connecting sql
Tag : sql , By : Revision17
Date : March 29 2020, 07:55 AM
This might help you You can explicitly add the COLLATE keyword to change the default collation as follows: select * from Publisher
where Motor COLLATE Macedonian_BIN like '%" + ed + "%' ";
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utf-8 latin1 problem charset collation
Tag : mysql , By : Sigtryggur
Date : March 29 2020, 07:55 AM
With these it helps About your error: make sure you send SET NAMES utf8 to your SQL server before INSERTing the data.
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Problem with SQL Collation
Date : March 29 2020, 07:55 AM
around this issue Database collation is just the default setting for new columns. To change the collation of an existing column, you'd have to alter table. For example: alter table YourTable alter column col1 varchar(10) collate Arabic_CI_AI
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Collation Problem
Date : March 29 2020, 07:55 AM
I wish did fix the issue. You will have to specify according to which collation you wish to do the join (or where clause) See the example below on how to code this. create table x( id int, name varchar(256) collate SQL_SwedishStd_Pref_CP1_CI_AS)
create table y( id int, name varchar(256) collate SQL_Latin1_General_CP1_CI_AS)
insert into x values (1, 'Filip')
insert into y values (1, 'Filip')
select *
from x
join y
on x.name collate SQL_Latin1_General_CP1_CI_AS = y.name
select *
from x
join y
on x.name = y.name collate SQL_SwedishStd_Pref_CP1_CI_AS
alter table x alter column name varchar(256) collate SQL_Latin1_General_CP1_CI_AS
select *
from x
join y
on x.name = y.name
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brain-teaser R problem - programming problem solving in R
Date : March 29 2020, 07:55 AM
like below fixes the issue There is a linear time algorithm for this. This algorithm is well explained by orezvani in this post on Computer Science section of stackexchange. I translated the orezvani pseudo code in R: max_subset<-function(S,K){
R <- S %% K
Res <- c()
for(k in 1:(ceiling(K/2)-1)){
index_k = which(R==k)
index_K_k = which(R==(K-k))
if(length(index_k) >= length(index_K_k)){
Res <- c(Res, S[index_k])
}else{
Res <- c(Res, S[index_K_k])
}
}
print(R)
Res <- c(Res, S[which(R==0)][1])
if(K %% 2 == 0){
Res <- c(Res, S[which(R==(K/2))][1])
}
return(Res)
}
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