How do I get Min and max values to only print when "year" is entered?

#include<iostream>
#include<conio.h>
#include<string>

using namespace std;

int main()
{
    string word[100];
    string arr[100];
    int wordCount = 0;

    while(1)
    {
        cout<<"enter word: \n";
        cin>>word[wordCount];
        if(word[wordCount] == "quit")
        {  
            break;
        }
        ++wordCount;
    } 

    int arrCount = 0;
    for(int i = 0; i < wordCount; ++i)
    {                  
        bool found = false;   
        for (int j = 0; j < arrCount; ++j)
        {
            if (arr[j] == word[i])
            {
                found = true;
                break;
            }
        }
        if (!found)
        {
            arr[arrCount] = word;
            ++arrCount;
        }
    }                                                 

    for(int i = 0; i < arrCount; ++i)
    {
        cout<<arr[n]<<"\n";
    }

    getch();
}

/**
 * Localized date-time pattern characters. For example, a locale may
 * wish to use 'u' rather than 'y' to represent years in its date format
 * pattern strings.
 * This string must be exactly 18 characters long, with the index of
 * the characters described by <code>DateFormat.ERA_FIELD</code>,
 * <code>DateFormat.YEAR_FIELD</code>, etc.  Thus, if the string were
 * "Xz...", then localized patterns would use 'X' for era and 'z' for year.
 * @serial
 */
String  localPatternChars = null;

df = pd.DataFrame({'year':[2015, 2018],
                   'weekofyear':[10,12]})

dates = df.year*100+df.weekofyear
@adde
df['date'] = pd.to_datetime(dates.astype(str) + '0', format='%Y%W%w')
print (df)

   year  weekofyear  formatted_date       date
0  2015  10          201510         2015-03-15
1  2018  12          201812         2018-03-25

#added 0 only for demontration, you can remove it
df['formatted_date'] = df.year * 1000 + df.weekofyear * 10 + 0
df['date'] = pd.to_datetime(df['formatted_date'], format='%Y%W%w')
print (df)

   year  weekofyear  formatted_date       date
0  2015  10          2015100        2015-03-15
1  2018  12          2018120        2018-03-25

 df$answer_check <- ifelse(df$correct_option == df$my_chosen_answers,
                              "right",
                              "wrong")

df$answer_count <- ave(df$answer_check, df$answer_check, FUN = length)