Javascript swap array element to another index and removing the old index
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I'm wondering why the "splice" method is not the solution. Look at my sample code. I'm using splice there and no any references is lost... function Oo(s) {
this._s = s;
}
Oo.prototype.toString = function() {
return "-" + this._s+"-";
}
var a = [];
a.push(new Oo('x'));
a.push(new Oo('y'));
a.push(new Oo('z'));
a[3] = a[1];
alert(a); // -x-,-y-,-z-,-y-
a[3]._s = 'XX'; // let's change the newly added item
alert(a); // -x-,-XX-,-z-,-XX- <- 3 and 1 points to the same object!
a.splice(1, 1); // remove one element, starting from index = 1
alert(a); // -x-,-z-,-XX-
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Access a PHP array element by using a JavaScript variable as index
Date : March 29 2020, 07:55 AM
will help you You can define arrayName variable in JS and initialize it with the value from the server: var arrayName = <?php echo json_encode($arrayName); ?>;
$(".elementClass").each(function(index, id) {
$(id).html(arrayName[index-1]);
});
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Javascript/jQuery Get Array Element Index from element position/index
Date : March 29 2020, 07:55 AM
it fixes the issue I know this question is a bit weird, but here's the example: , This just requires a simple loop over the array: function indexOfPartial(array, value) {
for (var i = 0; i < array.length; i++) {
if (array[i].indexOf(value) >= 0) {
return i;
}
}
return -1;
}
var index = indexOfPartial(mesreponses, 'NB - Nude');
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MongoDB Query to count documents a where specific array index exists. Index is in javascript variable
Date : March 29 2020, 07:55 AM
this will help I have some data that looks like this: , You can embed index in js code You need something like this. function count(myguid, index) {
const query = {"guid": myguid};
query["v." + index + ".cnt"] = {$exists: true};
return db.MuCollection.count(query);
}
count("some-guid", 3);
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Find value and index of Javascript array element when the index meets another condition
Date : March 29 2020, 07:55 AM
will be helpful for those in need Another solution to this is using reduce() over the arra1: const arr1 = [0,1,1,0,1];
const arr2 = ["a","b","c","d","e"];
let res = arr1.reduce(
(acc, v, idx) => v ? acc.concat({val: arr2[idx], idx}) : acc,
[]
);
console.log(res);
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