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Cannot group JSON array because of typecasting error


Cannot group JSON array because of typecasting error

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Cannot group JSON array because of typecasting error
Tag : json , By : geo
Date : November 29 2020, 04:01 AM

To fix the issue you can do I have an API that returns an array of dictionaries and I'm trying to group it by the date key in each item using Swift's Dictionay(grouping:) function. The JSON looks like this: , Your code contradicts itself. When you say
let groupedByDate = Dictionary(grouping: json, by: {
    (item) -> String in
return (item as! [String:AnyObject])["date"]

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Typecasting to get Value from json object


Tag : javascript , By : Goeran
Date : March 29 2020, 07:55 AM
it should still fix some issue I'm having a bit of trouble working something out with regards to javascript and Json. , Well...
j[i]

PHP: Create a number of Json arrays from a Json Array based on the group on one key


Tag : php , By : user183345
Date : March 29 2020, 07:55 AM
Any of those help I have an JSON Array like following:- , Convert the JSON to a php array
/* use json_decode(..., true) for creating an array, not an object of StdClass */
$array = json_decode($json, true);
$temp_array = array();
foreach($array as $a){
    if(!isset($temp_array[$a['contract_no']])){
        $temp_array[$a['contract_no']] = array($a);
    }
    else{
        array_push($temp_array[$a['contract_no']], $a);
    }
}
$result = array_values($temp_array)
$array_counter = 1;
foreach($result as $r){
    $array_name = "array".$array_counter;
    $$array_name = $r;
    $array_counter++;
}
$temp_array = array();
foreach($array as $a){
    if(isset($a['contract_no']) && !empty($a['contract_no'])){
        if(!isset($temp_array[$a['contract_no']]) || !is_array($temp_array[$a['contract_no']])){
            $temp_array[$a['contract_no']] = array();
        }

        array_push($temp_array[$a['contract_no']], $a);
    }
}

Can I use typecasting functions inside group by clause?


Tag : sql , By : Gianluca Riccardi
Date : March 29 2020, 07:55 AM
this will help For having you need to use aggregation like this
having max(CONVERT(date,LogInDate))>= (getdate() - 6)
    select CONVERT(date,LogInDate),count(*)
        from Login where LogInDate< (getdate() - 6)
        group by CONVERT(date,LogInDate) 

How to convert a json array that have same dates but different times to another format of json array that group time and


Tag : php , By : harley.holt
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I have a json array with ids, datetimes and soldout attributes that looks like below: , Try
    $out = [];
    foreach($x as $x)
    {
        $date = strtotime($x['date']);
        $day = date('Y-m-d',$date);
        $time = date('h:i a', $date);
        if(!array_key_exists($x['fdate'],$out))
        {
            $out[$x['fdate']] = [
                'fdate' => $x['fdate'],
                'date'  => $day,
            ];
            $out[$x['fdate']]['times'][] = [
                'id' => $x['id'],
                'time'  => $time,
                'soldout' => $x['soldout']
            ];
        }
        else
        {
            $out[$x['fdate']]['times'][] = [
                'id' => $x['id'],
                'time'  => $time,
                'soldout' => $x['soldout']
            ];
        }
    }
    $res=[];
    foreach($out as $out)
    {
        $res[] = $out;
    }
    dd(json_encode($res));
[
    {
        "date":"2020-06-07",
        "fdate": "7 Jun",
        "times": [
            {
                "id":2,
                "time": "9:30 am",
                "soldout": true
            },
            {
                "id":3,
                "time": "5:00 pm",
                "soldout": false
            }
        ]
    },
    {
        "date":"2020-06-08",
        "fdate": "8 Jun",
        "times": [
            {
                "id":4,
                "time": "10:00 am",
                "soldout": false
            },
            {
                "id":5,
                "time": "6:30 pm",
                "soldout": true
            }
        ]
    }
]

Does typecasting if a conditional statement differ from typecasting in a regular C expression?


Tag : c , By : 66.
Date : March 29 2020, 07:55 AM
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