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JSON parsing assitance


JSON parsing assitance

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JSON parsing assitance
Tag : android , By : Manu
Date : November 29 2020, 04:01 AM

wish of those help I can log the JSON file in my app but I'm having troubles parsing the JSON file. I'm trying to get the name of each recipe so I can display it in a RecyclerView. I do need more data from the JSON later on, would it be better to do all the parsing at once or as needed? , The base object is an array of objects.
Try this:
JSONArray recipes = new JSONArray(jsonString); 

for(int i = 0; i < recipes.length(); i++){ 
    JSONObject recipe = recipes.getJSONObject(i); 
    Log.d(LOGTAG, "Recipe name: " + recipe.getString("name"));
}

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Parsing a large (30MB) JSON file with net.liftweb.json or scala.util.parsing.json gives OutOfMemoryException. Any recomm


Tag : json , By : waarg
Date : March 29 2020, 07:55 AM
With these it helps Those messages indicate that the application is spending more than 98% of its time collecting garbage.
I'd suspect that Scala is generating a lot of short-lived objects, which is what is causing the excessive GCs. You can verify the GC performance by adding the -verbosegc command line switch to java.
$JAVA_OPTS=-server -Xmx1024m -Xms1024m -Xmn2m -verbosegc -XX:+PrintGCDetails

SQL Server : need assitance parsing delimted data and returning a long concatenated string


Tag : sql , By : KT.
Date : March 29 2020, 07:55 AM
this one helps. Complaints against normalizing data aside (because it's often out of our control), here's a generalized solution:
Create Table List (ID int Primary Key, Codes nvarchar(300));
Create Table Code (Code nchar(2), Name nvarchar(100));

Insert List
Values
 (1, 'AA AB AC AD')
,(2, 'AA AC')
,(3, 'AB');

Insert Code
Values
 ('AA', 'Apple')
,('AB', 'Banana')
,('AC', 'Cantaloupe')
,('AD', 'Dough');
Go

With Matches As
(
Select List.ID, Code.Code, Code.Name
From List
  Join Code
  On List.Codes Like '%' + Code.Code + '%'
)
Select List.ID
  ,Names = (
      Select (
        Select Name + '; '
        From Matches
        Where Matches.ID = List.ID
        For XML Path(''), Type
      ).value('.[1]', 'nvarchar(max)')
  )
From List

Need assitance with IF statement and JSON


Tag : jquery , By : John Bentley
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further I am trying to figure out how I can use an if statement to filter my JSON results on a page. Each recipe has its own category and I am trying to be able to filter the information based on type category type and other paramaters. I only included some code for people to get the idea but when I run this I get nothing. Here is my code: , This line:
if (item.recipeCategories == "fall") {
if (item.recipeCategories.indexOf("fall") !== -1) {
if (item.recipeCategories.includes("fall")) {
var json = [
    {
        "recipeName": "Crispy Zucchini Fritte with Lemon Aioli",
        "recipeCategories": ["appetizers", "spring"],
	},
    {
        "recipeName": "Hummus Tahini",
        "recipeCategories": ["desserts", "fall"],
    }
];
$.each(json, function(i, item) {
    if (item.recipeCategories.indexOf("fall") != -1) {
        $("<div>").text(item.recipeName).appendTo(document.body);
    }
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

Need assitance with pulling JSON item


Tag : javascript , By : Jay Crockett
Date : March 29 2020, 07:55 AM
To fix the issue you can do You're overwriting the HTML every time through the loop, so the final result will just be from the last item in the array.
Instead, you should use an if statement, and only display the items that matches the UPC code you want.
     $.each(data, function(i, item) {
        if (item.itemFullUPC == "070796150012") {
            $('#recipeIngredients').append(
                "<ul>" + 
                    "<li>" + '1/2 tsp sugar' + "</li>" +
                    "<li>" + '1/2 tsp salt' + "</li>" +
                    "<li>" + '1/2 tsp salt' + "</li>" +
                    "<li>" + '1 pkg active dry yeast' + "</li>" +
                    "<li>" + '3/4 cup warm water' + "</li>" +
                    "<li>" + '2 tbsp ' + item.itemName + "</li>" +
                    "<li>" + '2 cups shredded mozzarella cheese' + "</li>" +
                "</ul>"
            );
        }
     }); 

Need assitance with matching JSON files


Tag : javascript , By : Keonne Rodriguez
Date : March 29 2020, 07:55 AM
I wish this helpful for you You can use Array.prototype.map() and Array.prototype.find()
var recipe = [{
  "recipeName": "Test",
  "id": "10",
  "ingredients": [{
    "ingredientNum": "070796501104",
    "ingredientMeasure": "1 bottle",
    "ingredientMisc1": "(33.8 fl oz)"
  }, {
    "ingredientNum": "070796000164",
    "ingredientMeasure": "1/2 cup",
    "ingredientMisc1": ""
  }]
}];

var product = [{
  "productName": "Tomatoes",
  "itemFullUPC": "070796501104"
}, {
  "productName": "Cherries",
  "itemFullUPC": "070796000164"
}];

recipe.ingredients = recipe[0].ingredients.map(function(o) {
  o.ingredientName = product.find(function(p) {
    return p.itemFullUPC === o.ingredientNum;
  }).productName;
  return 0;
});

console.log(recipe);
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