Bash function with only variables

Bash function with only variables

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Bash function with only variables
Tag : linux , By : abuiles
Date : November 29 2020, 04:01 AM

I wish this helpful for you If you have functions named datanode2 and datanode1, and you want to execute them in a loop, you could write like this:
for fun in datanode2 datanode1; do
datanode1() {

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BASH: Global variables aren't updateable in a function only when that function is piped (simple example)

Tag : linux , By : Ken
Date : March 29 2020, 07:55 AM
wish of those help A pipe creates a subshell. It's said in the bash manual that subshells cannot modify the environment of their parents. See these links:

bash: call function with variables vs function with arguments

Tag : bash , By : Hugo Hernan Buitrago
Date : March 29 2020, 07:55 AM
Hope that helps The question has nothing to do with Bash as such.
The #1 is the example of "Spaghetti" coding style (global variables) hated by most professionals and simply sane people. It will eventually cause a major problem when someone somewhere changes the parameter and the function starts misbehaving, and you won't have a clue of who/what has changed what where.

How to install a bash function containing variables using a bash script?

Tag : bash , By : Justin Bowers
Date : March 29 2020, 07:55 AM
this will help A here document is treated as a double-quoted string, so parameter expansions and command substitutions are evaluated before the command reads from them. Quote any part of the delimiter to have the here document treated as a single-quoted string.
cat <<\EOT >> ~/.bashrc
# ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

# create a file backup in ~/filebackup/ with timestamp
filebackup () { cp "${@}" ~/"filebackup/${@}_$(date +%Y-%m-%d_%H:%M:%S).bk"; }

Bash lost variables after function

Tag : bash , By : CookingCoder
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , The shell runs whatever present under (..) in a sub-shell and especially variables the defined lose their scope once the shell terminates. You needed to enclose the function within {..} which encloses a compound statement in bash shell to make sure the commands within are run in the same shell as the one invoked.
function askExp { read -ep "$1" -n "$2" -r "$3"; }
  echo hello world from $BASHPID
  echo hello world from $BASHPID

how to call a bash function providing environment variables stored in a Bash array?

Tag : bash , By : Tony Z
Date : March 29 2020, 07:55 AM
will be helpful for those in need I got two variables in a bash script. One contains the name of a function within the script while the other one is an array containing KEY=VALUE or KEY='VALUE WITH SPACES' pairs. They are the result of parsing a specific file, and I can't change this. , You can do like this:
declare -a funcenv=(MYVAR=test "MYVAR2='test2 test3'")
for pairs in "${funcenv[@]}"; do
    eval "$pairs"
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