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When do you exit the context of a pytest fixture?


When do you exit the context of a pytest fixture?

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When do you exit the context of a pytest fixture?
Tag : python-3.x , By : Ravenal
Date : November 28 2020, 04:01 AM

will be helpful for those in need I created a fixture to initialize a database , I simplified your test_db fixture to the following:
@pytest.fixture
def test_db():
    """Setup Database"""
    print("\nInitialized resources")
    try:
        yield test_db
    finally:
        print("\nFinally executed")
@pytest.mark.parametrize(
    "attrs, exception, std",
    [ ( "attrs1", "ErrorObject", "std",) ]
)
def test_bad_resoruce_create(test_db, attrs, exception, std):
    print("Doing testings")
    assert 1 == 1
============================= test session starts ==============================
platform linux -- Python 3.5.3, pytest-4.2.1, py-1.8.0, pluggy-0.9.0 -- /usr/bin/python3
cachedir: .pytest_cache
rootdir: , inifile:
plugins: flask-0.14.0
collected 1 item                                                               

try.py::test_bad_resoruce_create[attrs1-ErrorObject-std] 
Initialized resources
Doing testings
PASSED
Finally executed


=========================== 1 passed in 0.10 seconds ===========================
try:
    next(yielded_fixture)
except StopIteration:
    pass

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How do I use a common pytest fixture as a context manager?


Tag : python , By : Dov
Date : March 29 2020, 07:55 AM
wish of those help The framework was reworked to that the connection was done through a class that uses the __enter__ and __exit__ methods which control the context automatically.

Pytest Class level fixture runs for every method if there is an exception in the fixture


Tag : python , By : GunnarHafdal
Date : March 29 2020, 07:55 AM
may help you . pytest catches the SystemExit exception, which is reasonable when you think about it: if you're testing a function that happens to call sys.exit, you wouldn't want this to shut down your whole test suite.
Use pytest.exit instead of sys.exit, which signals to pytest that you want to really shut down the test suite.

How to override a pytest fixture calling the original in pytest 4


Tag : python , By : Vorinowsky
Date : March 29 2020, 07:55 AM
I wish did fix the issue. To inject custom behavior before the initial fixture is called you can create separate fixture with this behavior and use it before the initial fixture in parameter list of fixture that overrides previously defined:
@pytest.fixture(scope='session')
def inject_before():
    print('inject_before')

@pytest.fixture(scope='session')
def django_db_setup(inject_before, django_db_setup):
    print('inject_after')

pytest-mock patch context manager not restoring object on exit


Tag : python , By : user90210
Date : March 29 2020, 07:55 AM
To fix the issue you can do With pytest-mock, teardown is done when exiting the fixture context. The mocker.patch object is not just a simple alias for mock.patch.
You should not need context managers within the test functions when writing pytest-style tests, and in fact the purpose of the pytest-mock plugin is to make the use of context managers and function decorators for mocking unnecessary.
from unittest.mock import patch

def test_main_2():
    with patch('module_a.MyClass.value', return_value=20):
        value = AnotherClass().get_value()
        assert value == 20
    value = AnotherClass().get_value()
    assert value == 10

Reuse an existing context manager as a pytest fixture


Tag : python , By : TheDave1022
Date : March 29 2020, 07:55 AM
hope this fix your issue Created a simple context manager, used it as the fixture and called that fixture in test.
class ContextManager():
    def __init__(self):
        print('init method called')

    def __enter__(self):
        print('enter method called')
        return self

    def __exit__(self, exc_type, exc_value, exc_traceback):
        print('exit method called')
import pytest
import createContextManager as ccm

@pytest.fixture(name ="c")
def check():
    with ccm.ContextManager() as cm:
        yield "hello"

@pytest.mark.stackoverflow
def test_checkficture(c):

    assert c =="hello", 'failed'
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