Remove duplicate entries in list using python
Tag : python , By : Lunis Neko
Date : March 29 2020, 07:55 AM
Hope that helps You probably want to use an O(1) lookup to save yourself a full scan of the elements while adding, and like Caol Acain said, sets is a good way to do it. What you want to do is something like: outlist=[]
added_keys = set()
for row in parsed_in:
# We use tuples because they are hashable
lookup = tuple(row[:3])
if lookup not in added_keys:
outlist.append(row)
added_keys.add(lookup)
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How to remove duplicate entries from a list in python
Tag : python , By : user183954
Date : March 29 2020, 07:55 AM
like below fixes the issue Although your hash-table implementation could be made more concise, readable, and idiomatic, with a small boost in speed, I suspect that isn't what your interviewer was disappointed in.
More likely, he pushed you for a better solution in hopes that you would come up with an argument why your solution was effectively optimal, but instead, you searched for a while and gave up.
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in python, how I append the index of a certain string in a list to another list if there are duplicate entries in the fi
Date : March 29 2020, 07:55 AM
wish of those help Say I have a list K, and a list B. If an entry in K fulfills my condition x, I want the index of that entry in my list B. The problem is since there are duplicate entries in the first list, using k.index only gives me the index of the first occurrence in that list. Here's what I have: , Here is a simple solution: for n, item in enumerate(k):
if item == x:
b.append(n)
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How to remove duplicate entries from a list of list
Tag : chash , By : Angel Paunchev
Date : March 29 2020, 07:55 AM
it helps some times You can use some handy Linq extension methods to get the job done. SelectMany will flatten the lists and select all the items, and Distinct will remove any duplicates: List<string> mergedLists = ListsToMerge.SelectMany(x => x).Distinct().ToList();
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python removal of duplicate entries in list and print output of unique list
Date : March 29 2020, 07:55 AM
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