Is there a better way to perform URL pattern matching in C++ than iteration?
Tag : cpp , By : Govind Bhavan
Date : March 29 2020, 07:55 AM
With these it helps The way I see it, you could split the URL into its components (using one of the suggestions in here maybe), and then use a decision tree to find the correct pattern. In this tree, every node would be a regular expression that matches a particular component of your URL, and the leaves would be the values you currently store in your map: session
| \
| 1
|
([0-9a-fA-F-]+)
/ | \
/ | \
url back element
| | | \
| | | 5
2 3 |
([0-9a-fA-F-]+)
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RESTKit 2.0: Pattern string must not be empty in order to perform pattern matching
Tag : ios , By : Nathan Good
Date : March 29 2020, 07:55 AM
I hope this helps you . When you create responseDescriptor this is added to the RKObjectManager you use pathPattern:nil. This is not permitted. You must specify a path pattern as RestKit must lookup the appropriate response descriptor to apply to the received response.
Later, you again use pathPattern:nil, but this is directly with an RKObjectRequestOperation. In this case it is allowed (and thus works) because you have provided an explicit list and no lookup is required.
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Perform pattern matching and guard at the same time
Tag : haskell , By : scott.sizemore
Date : March 29 2020, 07:55 AM
hope this fix your issue I want to perform pattern matching over a Maybe expression and apply a guard at once, something like: , This can be accomplished with a normal case block: case myFunction 333 of
Just val | val > 0 -> "> 0 " ++ show val
| val == 0 -> "== 0 " ++ show val
| val < -5 && val > -10 -> "< -5 and > -10 " ++ show val
_ -> "otherwise"
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How to perform pattern matching between two strings?
Date : March 29 2020, 07:55 AM
seems to work fine How about the following approach. Split each into words, lowercase each word and store in a set. x must then be a subset of y. So for your example it will fail as 16 does not match 64: x = "Apple iPhone 6(Silver, 16 GB)"
y = "Apple iPhone 6 64 GB GSM Mobile Phone (Silver)"
set_x = set([item.lower() for item in re.findall("([a-zA-Z0-9]+)", x)])
set_y = set([item.lower() for item in re.findall("([a-zA-Z0-9]+)", y)])
print set_x
print set_y
print set_x.issubset(set_y)
set(['apple', '16', 'gb', '6', 'silver', 'iphone'])
set(['apple', 'mobile', 'phone', '64', 'gb', '6', 'gsm', 'silver', 'iphone'])
False
set(['apple', '16', 'gb', '6', 'silver', 'iphone'])
set(['apple', '16', 'mobile', 'phone', 'gb', '6', 'gsm', 'silver', 'iphone'])
True
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How would I perform this text pattern matching
Tag : cpp , By : Trevor Cortez
Date : March 29 2020, 07:55 AM
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