Why does R paste more decimals than have been rounded, but only sometimes?

Why does R paste more decimals than have been rounded, but only sometimes?

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Why does R paste more decimals than have been rounded, but only sometimes?
Tag : r , By : Bo.
Date : November 28 2020, 04:01 AM

I think the issue was by ths following , There's rounding error, but in this case R is not handling it nicely.
Any representation of floating-point numbers in R is done as double, which means 53 bits of precision, approximately 16 digits. That's also for the 99.7, you can see where it breaks down:
print(99.7, digits=16) # works fine
print(99.7, digits=17) # Adds a 3 at the end on my platform
print(100-99.7, digits=14) # works fine
print(100-99.7, digits=15) # Allready rounding error at digits=15
paste(format(100 - y, digits=14), "is the inverse")

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Javascript: formatting a rounded number to N decimals

Tag : javascript , By : dnyaneshwar
Date : March 29 2020, 07:55 AM
I hope this helps you . That's not a rounding ploblem, that is a display problem. A number doesn't contain information about significant digits; the value 2 is the same as 2.0000000000000. It's when you turn the rounded value into a string that you have make it display a certain number of digits.
You could just add zeroes after the number, something like:
var s = number.toString();
if (s.indexOf('.') == -1) s += '.';
while (s.length < s.indexOf('.') + 4) s += '0';

How to stop decimals being rounded up or down using php

Tag : php , By : Bado
Date : March 29 2020, 07:55 AM
help you fix your problem It's working well for me, try this:
echo floor(67.9699 * 100) / 100;

how to print double using rounded number of decimals

Tag : chash , By : Blight
Date : March 29 2020, 07:55 AM
I hope this helps you . It's important to understand that float and double don't retain trailing zeroes. You have two options:
Specify the format to include the number of decimal places you're interested in Use decimal, which does retain trailing zeroes

Why in c# 2.135 is always rounded (using 2 decimals) to 2.13

Tag : chash , By : Grant
Date : March 29 2020, 07:55 AM
this one helps. To answer the question from your title:
2.135 is not always rounded(using 2 decimals) to 2.13, this just happens in your case because you are using a binary floating point data type. (As leppie pointed out, 2.135 cannot be represented accurately as a double, please note also that Microsoft seems to disinguish between decimal and floating point types, even though decimal also fits the definition)
decimal val1 = 2.135m;
decimal val2 = 3.135m;

Console.WriteLine("decimal val1({0}) rounded = {1}", val1, Math.Round(val1, 2));
Console.WriteLine("decimal val2({0}) rounded = {1}", val2, Math.Round(val2, 2));

double dval1 = 2.135;
double dval2 = 3.135;

Console.WriteLine("double val1({0}) rounded = {1}", dval1, Math.Round(dval1, 2));
Console.WriteLine("double val2({0}) rounded = {1}", dval2, Math.Round(dval2, 2));

How can I prevent decimals being rounded when using DecimalFormat?

Tag : java , By : k19k
Date : March 29 2020, 07:55 AM
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