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Noncapturing patterns with vi or sed


Noncapturing patterns with vi or sed

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Noncapturing patterns with vi or sed
Tag : regex , By : nobodyzzz
Date : November 28 2020, 04:01 AM

fixed the issue. Will look into that further idk if that first long space is a tab or multiple blanks so this will work either way assuming the captured string doesn't contain any backreference metacharacters (e.g. &)::
$ awk -F'  +|\t' '{gsub(/[|]|$/,"+"$1"&")}1' file
G1778-BRAZIL    .A3_Alagoas+G1778-BRAZIL|.A5_Amazonas+G1778-BRAZIL|.B3_Bahia+G1778-BRAZIL|.C4_Ceara+G1778-BRAZIL|.D5_Distrito Federal+G1778-BRAZIL|.E8_Espirito Santo+G1778-BRAZIL|.G6_Goias+G1778-BRAZIL|.G8_Guanabara+G1778-BRAZIL
G2807-ATLANTIC OCEAN    .B3_Baffin Bay+G2807-ATLANTIC OCEAN|.M4_Mexico, Gulf of+G2807-ATLANTIC OCEAN|.N55_North Atlantic Ocean+G2807-ATLANTIC OCEAN|.N6_North Sea+G2807-ATLANTIC OCEAN

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Regex.Match and noncapturing groups


Tag : chash , By : Kiltec
Date : March 29 2020, 07:55 AM
seems to work fine Can anyone explain why Regex.Match captures noncapturing groups. Can't find anything about it in MSDN. Why , Captures is different than groups.
matchResults.Groups[0]
matchResults.Groups[1],

Why does Regex.Match include noncapturing groups in the result?


Tag : chash , By : Si Gardner
Date : March 29 2020, 07:55 AM
Does that help Matching is not the same thing as capturing. (?:\d) simply means match a subpattern containing \d, but don't bother putting it in a capture group. Your entire pattern (?:\d)\w looks for a (?:\d) followed by a \w; it's functionally equivalent to \d\w.
If you're trying to match a \w only when it is preceded by a \d, use a lookbehind assertion instead:
System.Text.RegularExpressions.Regex.Match("b3a", @"(?<=\d)\w").Value

Noncapturing along with capturing match


Tag : chash , By : Jonathan
Date : March 29 2020, 07:55 AM
seems to work fine So you've got two problems to solve: first, you want to match ".mysite.com" but not capture it; second, you want to grab up to 10 alphabetic characters in the "subdomain" position.
First problem can be solved by using a capturing group. The regex
([a-z]{2,10})\.mysite\.com
\b([a-z]{2,10})\.mysite\.com
\b(\w{2,10})\.mysite\.com

noncapturing group explanation within a positive lookahead


Tag : regex , By : Mighty Mac
Date : March 29 2020, 07:55 AM
I hope this helps . No, (?=.*(?:[a-z])) means that there could be whatever but must finish with a lowercase letter.
This regex means:
/^(?=[A-Za-z0-9\'\s\d\.]{2,50}$)(?=.*(?:[a-z]))[a-zA-Z0-9]+[A-Za-z0-9\'\s\.]+$/m
/^(?=[A-Za-z\d'\s.]{2,50}$)(?=.*[a-z])[a-zA-Z\d]+[A-Za-z\d'\s.]+$/m

How to write noncapturing groups in egrep


Tag : development , By : Sascha Brossmann
Date : March 29 2020, 07:55 AM
wish help you to fix your issue grep -P forces grep to use the Perl regexp engine.
egrep is the same as grep -E and it forces grep to use the ERE (extended regular expression) engine, that does not support lookahead.
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