Formatting php array output
Date : March 29 2020, 07:55 AM
this one helps. You can declare the array before the while loop and you can push the values into it like $existing_users = array();
mysql_select_db($database_db, $db);
$result = mysql_query('SELECT * FROM clients') or exit(mysql_error());
while ($row = mysql_fetch_assoc($result)) {$existing_users[] = $row['shortcode'];}
print_r($existing_users);
|
Formatting an array output in c#
Tag : chash , By : kangfoo2
Date : March 29 2020, 07:55 AM
To fix this issue Use the String.Join method to make a string with the values in the array: string values = String.Join(", ", number);
Console.Write("For the list = <{0}> the sum of its elements is : {1}.", values, total);
string values = String.Join(", ", number.Select(n => n.ToString()));
|
Formatting array output into 9x9 box
Tag : java , By : UnKnownUser
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , First, you are adding the line break outside both of your loops, rather than at the end of the first loop, and second, for text formatting, you are better off using printf() than println(). Try something like this: for (int row = 0; row < multTable.length; row++) {
for (int column = 0; column < multTable[row].length; column++) {
multTable[row][column] = (row + 1) * (column + 1);
System.out.printf("%3d", multTable[row][column]);
}
System.out.println();
}
|
Formatting JSON output using pg-promise, encapsulating foreign keys as objects
Date : March 29 2020, 07:55 AM
around this issue pg-promise executes queries directly, and provides data exactly as it is sent by the server. It does not do any additional transformation, as it is not an ORM. If you want your data transformed the way you described, then just do it yourself, for it is trivial.
|
Formatting API Array Output
Tag : php , By : fedorafennec
Date : March 29 2020, 07:55 AM
hope this fix your issue You can try several different types of tests that may work empty($v), isset($v), is_null($v), or strcmp($v, ""). Since this is a JSON it is most likely that blank values in $v are stored as a "". Therefor you should probably start with empty(). But try it and see. foreach ($json['Results'][0] as $k => $v){
if (!empty($v)){
$results .= ($k).": ".($v).'<br />';
}
}
|