Regex on a substring

Regex on a substring

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Regex on a substring
Tag : regex , By : Frank Bradley
Date : November 28 2020, 04:01 AM

I think the issue was by ths following , You can quantify (with a range) a "dot anything" wildcard token and anchor the pattern to start of string to achieve this:

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How can I create a regex that parses all lines of a string for a substring, and returns a match only if the substring is

Tag : chash , By : John Bentley
Date : March 29 2020, 07:55 AM
I wish did fix the issue. You can make use of the flag RegexOptions.SingleLine to make the dot you're using in your regex match newlines:
new Regex(@"^((?!message 1).)*$", RegexOptions.SingleLine | RegexOptions.IgnoreCase);

Regex: Find substring starts with AND end with from a string and replace a word from substring

Tag : javascript , By : user107021
Date : March 29 2020, 07:55 AM
hop of those help? Possible inputs:
var re = /^(\S+)\s*\S*(?=,)/gmi; 
var str = 'Hi John, I have recently..\nhi , I have...\nHi Hans, I have...\nHi, I have...';
var subst = '$1 David'; 

var result = str.replace(re, subst);

How to extract substring(html) and another substring (which will be used for regex) and place it all in proper format?

Tag : java , By : cnemelka
Date : March 29 2020, 07:55 AM
With these it helps I have a giant string which contains the below code and I need to extract contains in such a way that,if any HTML comes append it and if any substring that contains following pattern, create a link out of it and it in proper format and place and goes on. , Solution
public static void main(String[] args) {

    StringBuilder str = new StringBuilder("<div id=\"contentPermission\">"
            + "  [[MI44,MI304,MI409,MI45,MI264,MI108,MI46,MI47,MI48,MI49,MI50,MI51,MI52,MI58,MI530]]"
            + "</div><div>&nbsp;</div><p>&nbsp;</p><div>&nbsp;</div><p>&nbsp;</p><p>[[LP1137]]</p>");

    System.out.println("Before " + str.toString()+"\n\n\n");

    Pattern pattern = Pattern.compile("\\[{2}.[^\\]]*\\]{2}");
    Matcher matcher = pattern.matcher(str);


        String codes = matcher.group(0);
        codes = codes.substring(2, codes.length()-2);

        StringBuilder urls = new StringBuilder();
        for(String code:codes.split(",")){
            urls.append("<a href=\"index?page=content&id=" + code + "></a>\n");
        str = new StringBuilder(matcher.replaceFirst(urls.toString()));
        matcher = pattern.matcher(str);

    System.out.println("Replaced " + str.toString());

How do I replace a substring with another string that contains that substring as a part of it using regex in python

Tag : python , By : Raghu
Date : March 29 2020, 07:55 AM
wish help you to fix your issue Suppose I have a string "03/25/93" which is in a pandas series. I want to find /93 first and then replace it with /1993. How do I go about it? , Use \1 to reference a match
>>> df.str.replace(r'/(\d{2})$', r'/19\1')
0    03/25/1993
1     6/18/1985
2      7/8/1971
3     9/27/1975
4      2/6/1996
dtype: object

Regex expression to replace a string containing a substring with the substring only in a DataFrame

Tag : python , By : Skee
Date : March 29 2020, 07:55 AM
will help you I am trying to replace all strings within a Python dataframe column that contain a certain substring, with only the substring itself. Preferably it would be an 'inplace=True' sort of result. , Use:
df['brand'] = np.where(df['brand'].str.contains('brand1'), 'brand1',df['brand'])
0   brand1 & brand2
1   brand6
2   brand1/brand3
3   brand9
4   brand4 brand3
5   brand1 and brand 6
0   brand1
1   brand6
2   brand1
3   brand9
4   brand4 brand3
5   brand1
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