Java method overloading as a combined user input
Date : March 29 2020, 07:55 AM
around this issue I am currently working with an array list of a movie rental store. I am trying to make a parameter of movieID,renterID, and movieName. I would like to make all of these one method when I run the program, so the user can input 1 or 2 or all 3 of these parameters. Is this possible to do this from one method/if so, how? Also, can I make it where java accepts a blank as a null instead of having the user type null? The specific code I am working with is below. public void methodOverloading(Integer movieID, Long renterID, String movieName)
{
System.out.println();
if(MovieID != null) {
this.printMovieInforForMovieID(movieID);
}
if(RenterID != null) {
this.printMovieInforForRenterID(renterID);
}
if(MovieName != null) {
this.printMovieInforForMovieNameContaining(movieName);
}
}
|
Is there an option to enable overloading of user-defined symbols in cvc4 for SMT input?
Date : March 29 2020, 07:55 AM
Hope this helps Unfortunately, CVC4 does not have an option to support overloaded user symbols. Each user symbol must be unique.
|
Is the term function overloading equivalent to method overloading in Java?
Date : March 29 2020, 07:55 AM
I hope this helps . From a pragmatic point of view, I would go with function overloading. But when thinking in pure Java terms, the one and only term is methods. Java does not know functions, only methods. Besides the interface Function.
|
How Can I get input from user until user enter the right input in java?
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further In your while loop, you check for OR (||). Replace it by AND (&&) while (!MenuLanguage.equalsIgnoreCase("1") && (!MenuLanguage.equalsIgnoreCase("English")) &&
(!MenuLanguage.equalsIgnoreCase("2")) && (!MenuLanguage.equalsIgnoreCase("Persian")) )
|
Overloading input the base class inside overloading input derived class
Tag : cpp , By : user160048
Date : January 02 2021, 06:48 AM
help you fix your problem In order to get the Base part of d, you need to cast to Base&. What you get with your cast is a temporary Base object, which can't be passed as a non-const reference argument. Derived d;
Base &b = d;
std::cin >> b;
struct Base
{
virtual void read(std::istream& is) { ... }
};
std::istream& operator>> (std::istream &in, Base &b)
{
b.read(in);
return in;
}
struct Derived: Base
{
void read(std::istream& is) override { Base::read(is); ... }
};
|